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2 years ago

5

In a right triangle, if the length of the hypotenuse is 10 and the length of one of the other sides is 6, what is the length of

the third side? (Simplify Answer)

1 answer:

Andrew [12]2 years ago

4 0

Answer:

8

Step-by-step explanation:

10^2=100 6^2=36 100-36=64 sqrt64=8

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Torrey has $20 to buy a birthday present for her that she does this to buy a CD for $18 the sales tax is 7% does she have enough

Effectus [21]

No, because she will go over by .57 cents. So she won't be able to buy the gift. You can find the answer by dividing 18 by 7 and adding that answer to 18 to get the amount total you owe including tax.

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3 years ago

(x+2y = 10<br> 16y=-3x+30

Harlamova29_29 [7]

Answer:

x = 10, y = 0

Step-by-step explanation:

x + 2y = 10

x = 10 - 2y <em>(</em><em>B</em><em>r</em><em>i</em><em>n</em><em>g</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>2</em><em>y</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>r</em><em>i</em><em>g</em><em>h</em><em>t</em><em>)</em>

16y = -3x + 30

16y = -3(10 - 2y) + 30 <em>(</em><em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>x</em><em> </em><em>t</em><em>o</em><em> </em><em>1</em><em>0</em><em> </em><em>-</em><em> </em><em>2</em><em>y</em><em>)</em>

16y = -30 + 6y + 30 <em>(</em><em>E</em><em>x</em><em>p</em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em>r</em><em>a</em><em>c</em><em>k</em><em>e</em><em>t</em><em>s</em><em>)</em>

10y = 0 <em>(</em><em>B</em><em>r</em><em>i</em><em>n</em><em>g</em><em> </em><em>y</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>l</em><em>e</em><em>f</em><em>t</em><em>)</em>

<u>y</u><u> </u><u>=</u><u> </u><u>0</u>

x = 10 - 2(0) <em>(</em><em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>0</em><em>)</em>

<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>0</u>

<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>0</u><u>,</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>0</u>

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2 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

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2 years ago

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patriot [66]

Its 28 my dude hope this helps

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3 years ago

What is the value of a?

AlekseyPX

Answer:

Sorry can't help try asking someone else

Step-by-step explanation:

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2 years ago