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kramer
3 years ago
9

Does 10, 9, and 15 make a right triangle?

Mathematics
1 answer:
postnew [5]3 years ago
4 0

the triangle formed by sides 10, 9 and 15 units can't be a right angled triangle, because they doesn't form the pythagorean triplet, that is the sum of squares of the smaller sides isn't equal to the square of largest side,

sum of squares of smaller sides

=》

10 {}^{2}  + 9 {}^{2}

=》

100 + 81

=》

181

now, square of largest side (hypotenuse)

=》

{15}^{2}

=》

225

they aren't equal, proved

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Answer:

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25-(-3)= 28

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6-(-9)= 15

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3 years ago
nate walks 25 meters in 13.7 seconds. if he walks at the same rate, which of the following is closest to the distance he will wa
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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

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7 0
3 years ago
PLEAS HELP!!! Examine the graph.
raketka [301]
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CD
7 0
3 years ago
Read 2 more answers
Helpppppp plsssssssss
bekas [8.4K]

Answer:

C

Step-by-step explanation:

The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.

x is the hypotenuse (side opposite of 90 degree angle).

We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

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<em>Now we can use property of radical  \sqrt{x}\sqrt{y}  =\sqrt{x*y}  to simplify:</em>

x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}

Correct answer is C

6 0
3 years ago
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