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alexira [117]
2 years ago
10

Pllssss helpp with thisss mathhh!!!!!!!

Mathematics
2 answers:
Neporo4naja [7]2 years ago
6 0
It is B 2 that’s it
Ierofanga [76]2 years ago
5 0

Answer:NOPE I WAS WRONG SORRY ITS ANSWER NUMBER 2

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The midpoint of A (-4, 2) and B(8, 5) is
Norma-Jean [14]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -4}}\quad ,&{{ 2}})\quad 
%  (c,d)
&({{ 8}}\quad ,&{{ 5}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 8}} -4}{2}\quad ,\quad \cfrac{{{ 5}} + {{ 2}}}{2} \right)
8 0
3 years ago
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svetoff [14.1K]
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3 0
3 years ago
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What is the square root of 5x^2 = 300
vesna_86 [32]

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Step-by-step explanation:

We need to find the square root of 5x^2 = 300

Writing in mathematical form:

5x^2=300

Divide both sides by 5

\frac{5x^2}{5}=\frac{300}{5}

x^2=60

Taking square root on both sides

\sqrt{x^2}=\sqrt{60}

x=\pm (\sqrt{2\times 2\times 3\times 5})

x=\pm (\sqrt{2^2 \times 3\times 5})

x=\pm (2\sqrt{3\times 5})

x=\pm (2\sqrt{15})

x=2\sqrt{15},\,\,x=-2\sqrt{15}

So, values of x are: x=2\sqrt{15},\,\,x=-2\sqrt{15}

Keywords: Square root

Learn more about square root at:

  • brainly.com/question/3511750
  • brainly.com/question/4034547

#learnwithBrainly

7 0
3 years ago
You fly a hot air balloon 3.5 miles above the ground. What is the measure of BD⌢, the portion of Earth that you can see? Round y
STatiana [176]

Answer:

\Delta s \approx 334.545\,m

Step-by-step explanation:

Let assume that Earth is a sphere, the following trigonometric diagram is constructed and presented below. The central angle is given by this inverse trigonometric equation:

\theta = 2\cdot \cos^{-1} \left(\frac{r}{r+h} \right)

\theta = 2\cdot \cos^{-1}\left(\frac{4000\,mi}{4000\,mi+3.5\,mi} \right)

\theta = 4.792^{\circ}

The distance of the portion of Earth that can be seen is:

\Delta s = \frac{4.792^{\circ}}{360^{\circ}}\cdot (2\pi)\cdot (4000\,mi)

\Delta s \approx 334.545\,m

7 0
3 years ago
The vertices of angleABC are A(1,1) B(5,1) C(3,3) drawl the triangle and it’s image A’B’C’ reflected in the Y axis. What are the
nevsk [136]

For any point reflected in the y- axis

(x, y ) → (- x, y )

A(1, 1) → A'(- 1, 1)

B(5, 1 ) → B'(- 5, 1 )

C(3, 3 ) → C'(- 3, 3 )


6 0
3 years ago
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