Answer:
Step-by-step explanation:
![\sqrt[3]{\frac{27t^{9} }{729} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B27t%5E%7B9%7D%20%7D%7B729%7D%20%7D)
27 is a perfect cube for 
and 729 is a perfect cube for 
![\sqrt[3]{\frac{3^{3} t^{9} }{9^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3%5E%7B3%7D%20t%5E%7B9%7D%20%7D%7B9%5E%7B3%7D%20%7D%20%7D)
now you can pull out the numbers from under the root, for t (divide the exponent by 3)
now simply to
Step-by-step explanation:
a^2 + b^2 = c^2
(x+2)^2 + 4x^2 = (3x+4)^2
(x+2)(x+2)+ 4x^2= (3x+4)(3x+4)
x^2 + 2x + 2x + 4 + 4x^2 = 9x^2 + 12x + 12 x + 16
5x^2 + 4x + 4 = 9x^2 + 24x + 16
-4x^2 - 20x - 12 = 0
now we can use the quadratic formula
(-b±√(b²-4ac))/(2a)
I can't type all this so
.....
x = -0.697224362 or -4.302775638
AB can't be negative so it's the first one
so it's equals to 1.302775638
If it’s only reflected over the y axis then only the x values change
Download the app Math then take a picture and it wil give u the answer.
