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Semmy [17]
3 years ago
15

Explain why ABC cannot be mapped onto EFG by a reflection of ABC over the -axis followed by a slide of 8 units to the left.

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

It won't be the same shape and length and width I think

Step-by-step explanation:

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What is the volume of the figure?
tatyana61 [14]

Answer:

volume of a cone = \pi r^{2} h/3

                          \pi  = 22/7 or 3.14

              r (radius) = 8 ft

             h (height) = 16 ft

∴ volume = 22/7 * 8 * 8 * 16/3

                =  3.14 * 64 * 16/3

                = 1072.76190476 ft^{3}

hope this answer helps you.....

please mark as brainliest ..... thank you....

8 0
3 years ago
The function y = -3x + 5 is transformed by reflecting it over the y axis. What is the equation of the new function? *
SpyIntel [72]

Answer:

x= −1/3 y+5/3

Step-by-step explanation:

Let's solve for x.

y=−3x+5

Step 1: Flip the equation.

−3x+5=y

Step 2: Add -5 to both sides.

−3x+5+−5=y+−5

−3x=y−5

Step 3: Divide both sides by -3.

−3x

−3

=

y−5

−3

x=

−1

3

y+

5

3

4 0
3 years ago
Tropical islands have many rainstorms during the afternoon heat. One particular tropical island has a 79% chance of a rainstorm
erma4kov [3.2K]

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7 0
3 years ago
Read 2 more answers
The first term and the common ratio of a G.P are respectively 3 and 1/2.write down the first five terms​
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

a =3 ;r  = 1/2

first term = 3

second term = 3*1/2 = 3/2

third term = 3/2 * 1/2 = 3/4

Fourth term = 3/4*1/2 = 3/8

Fifth term = 3/8 * 1/2 = 3/16

GP is: 3,3/2,3/4,3/8,3/16......

8 0
4 years ago
The height of a fountain’s water stream can be modeled by a quadratic function. Suppose the water from a jet reaches a maximum h
Grace [21]

Answer:

h(d)= -2d^2 +4d +6

Step-by-step explanation:

Vertex (1,8)

Landing Point (3,0)

Applying the vertex formula, a quadratic equation can be described by its vertex v(x,y) as follows:

h=a*(d-x)^2 +y

Since the vertex in this situation is at v (1,8):

h=a*(d-1)^2 +8

To solve for 'a', apply the other given point (landing point) into the equation:

0=a*(3-1)^2 +8\\4a= - 8 \\a=-2

Expanding the equation yields:

h=-2*(d-1)^2 +8\\h=-2(d^2 -2d +1) +8\\h= -2d^2 +4d +6\\

5 0
4 years ago
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