Pretty good so far its hard also.
No 1+2=3 which is less than 5
The two sides must equal more than the third one when added
price of one message = 1.35 ÷ 9
1.35 ÷ 9 = 0.15
0.15 • 118 = ( 3 ÷ 20 ) • 118
118 • 3 = 354
354 ÷ 20 = 177 ÷ 10 = $17.7 to send 118 messages
please give brainliest
Answer:
Every student would have five markers.
Step-by-step explanation:
There would be 20 students, and 100 markers which is 20/100. You would reduce that fraction to 1/5. Therefore, every student would have 5 markers.
Answer:
algebraic expression: 3x + 2b
coefficients: 3 and 2
variables: w and b
# of terms: 2
constant: 0
algebraic expression: 6xy - 2c + 4
coefficients: 6 and -2
variables: x, y, and c
# of terms: 3
constant: 4
algebraic expression: 2/3 y - 3p
coefficients: 2/3 and -3
variables: y and p
# of terms: 2
constant: 0
