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GalinKa [24]
3 years ago
15

A roofer leaned a 16-foot ladder against a house. If the base of the ladder is 5 feet from the house, how high up the house does

the ladder reach?
Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

15.20feet

Step-by-step explanation:

Length of the ladder = 16foot (hypotenuse)

BAse of the ladder from the house = 5feet (adjacent)

height of the house = x (opposite)

Using the pythagoras theorem

hyp^2 = opp^2 + adj^2

16^2 = 5^2 + opp^2

256 = 25 + opp^2

opp^2 = 256-25

opp^2 = 231

opp =√231

opp = 15.20

Hence the house is 15.20feet high up the house

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i hope this helps!

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Answer:

\frac{16}{25}

Step-by-step explanation:

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What is the area of rectangle ABCD?
larisa86 [58]

Answer:

Area = 12 square units

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3 years ago
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Help Homework.
Ksju [112]

Answer:

1/24

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10/24 - 9/24 = ?

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8 0
3 years ago
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Solve 3-2cos²x-3sinx=0 for 0≤x≤360
crimeas [40]
<span>3-2(Cosx)^2 - 3Sinx = 0.

Recall (Sinx)^2 + (Cosx)^2  = 1.
Therefore  (Cosx)^2 =  1 - (Sinx)^2
Substitute this into the question above.

</span><span>3-2(Cosx)^2 - 3Sinx = 0
3 - 2(1 - (Sinx)^2)  - 3Sinx = 0  Expand
3 - 2 + 2(Sinx)^2  -  </span><span><span>3Sinx = 0</span>
1 + 2(</span><span>Sinx)^2  - 3Sinx  = 0  Rearrange
2(Sinx)^2 </span><span><span>- 3Sinx + </span>1  = 0 
Let p = Sinx
2p^2  -  3p + 1  = 0    Factorise the quadratic expression
2p^2 - p - 2p +1 = 0
p(2p -1) - 1(2p -1) = 0
(2p-1)(p -1) = 0

Therefore  2p-1=0    or  (p-1) = 0
2p=0+1    or  (p-1) = 0
2p=1       or    p = 0 +1.
p=1/2       or  p = 1            Recall p = Sinx

Therefore Sinx = 1/2 or 1.
For  0<u><</u>x<u><</u>360

Sinx =1/2,  x = Sin inverse (1/2) , x = 30, 
                                   (180-30)- 2nd Quadrant = 150 deg
Sinx = 1,  x = Sin inverse (1) , x = 90

Therefore x = 30,90 & 150 degrees.

Cheers.</span>
7 0
3 years ago
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