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GalinKa [24]
3 years ago
15

A roofer leaned a 16-foot ladder against a house. If the base of the ladder is 5 feet from the house, how high up the house does

the ladder reach?
Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

15.20feet

Step-by-step explanation:

Length of the ladder = 16foot (hypotenuse)

BAse of the ladder from the house = 5feet (adjacent)

height of the house = x (opposite)

Using the pythagoras theorem

hyp^2 = opp^2 + adj^2

16^2 = 5^2 + opp^2

256 = 25 + opp^2

opp^2 = 256-25

opp^2 = 231

opp =√231

opp = 15.20

Hence the house is 15.20feet high up the house

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Answer:

b = -152

Step-by-step explanation:

  1. 7 + 12 = 19
  2. Plug 19 in: \frac{b}{19} = -8  
  3. Multiply each side by 19 to cancel out the 19 under b. It should now look like this: b = -152

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3 years ago
Given RS = 6, ST = 3, and SL = 4, find SM.
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Equation of y-intercept of 0 with a slope of 1 in slope intercept form
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Simplify the expression (2x − 9)(x + 6)
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<u>Answer:  </u>

Simplified form of given expression (2x – 9 )( x + 6 )  is 2 \mathrm{x}^{2}+3 \mathrm{x}-54

<u> Solution: </u>

We need to simplify following expression.

(2x – 9) ( x + 6)  

For sake of simplicity lets first assume 2x – 9 = A

So expression becomes A(x+6)

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Hence simplified form of given expression (2x – 9 )( x + 6 )  is = 2 \mathrm{x}^{2}+3 \mathrm{x}-54

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