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olga55 [171]
3 years ago
12

Is 69 degrees a vertical or adjacent? please help thank you

Mathematics
1 answer:
Anna71 [15]3 years ago
3 0

Answer:

Adjacent

Step-by-step explanation:

Vertical would be 90 degrees

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Fine area in triangle.​
choli [55]
Answer:Area of triangle is 18cm2
There is a dotted line to show us how to do,we know the dotted means we don’t actually work that part out.
1. The bottom added together = 11,now : (11x6) ÷ 2 = 33cm2.
2.The part where there is a dotted triangle: (6x5) ÷ 2 = 15cm2.
3. 33 - 15 = 18.



3 0
2 years ago
17. Identify the amplitude, period, and vertical shift for the
Stella [2.4K]

Answer:

f(x)=2cos(x+\frac{\pi}{2})+3

Step-by-step explanation:

Because the function is symmetric about the y-axis, using the cosine function is most appropriate.

<u>Refer to the equation for a cosine function:</u>

<u />f(x)=acos(bx+c)+d<u />

Amplitude: |a|

Period: \frac{2\pi}{|b|}

Phase shift: -\frac{c}{b}

Midline: y=d

The amplitude would be the average of the maximum and minimum y-values of the function, which would be |a|=|\frac{5-1}{2}| =|\frac{4}{2}| =|2|=2.

The value of b in \frac{2\pi}{|b|} represents the length of the period, so since the length of the period is 2\pi, this means that b=\frac{2\pi}{|2\pi|} =1.

The phase shift, -\frac{c}{b}, describes the horizontal shift of a function. Because the phase shift is -\frac{\pi}{2}, then we can set up the equation -\frac{\pi}{2}=-\frac{c}{1} where we determine c=\frac{\pi}{2}.

The midline (or vertical shift), d, is the horizontal line that passes through between the maximum and minimum points, which the function oscillates. In this case, the midline would be located at the line y=3, therefore, d=3.

Putting all our information together, your final equation is:

f(x)=2cos(x+\frac{\pi}{2})+3

3 0
3 years ago
Rewrite in simplest terms:<br><br> -2 (3g - 8g +8) -9g
vovikov84 [41]

Answer:

1g - 16

Step-by-step explanation:

-2 (3g - 8g +8) -9g

-2(-5g +8) - 9g

10g - 16 + -9g

1g - 16

7 0
3 years ago
Read 2 more answers
Which sequence is modeled by the graph below?
tankabanditka [31]

We can see from points

(2,1) means for n = 2, a = 1

(3,3) means for n = 3, a = 3

(4,9) means for n = 4 , a= 9

Now try to see relation in outputs 1,3,9.

We can write 1 as 3^{0}

3 as 3^{1}

9 as 3^{2}

So (2,2) would mean for n =2, a = 1 or 3^{0}----------------(1)

(3,3) would mean for n = 3, a = 3 or 3^{1}-------------(2)

(4,9) would mean for n = 4, a = 9 or 3^{2}--------------------(3)

From (1) we can see for n =2, exponent on 3 is 0

From (2) we can see for n =3, exponent on 3 is 1

From (3) we can see for n =4, exponent on 3 is 2

So we can see the pattern whatever is n value its 2 less is the exponent on 3. So for n exponent on 3 will be n-2

For n = n, a = 3^{n-2}

Now looking at options given

option (A) \frac{1}{3} 27^{n-1} doesnt match to 3^{n-2}

so its incorrect

------------------------------------------------------------------------------------------------------

option (B) 27\frac{1}{3}^{n-1} doesnt match to 3^{n-2}

so its incorrect

----------------------------------------------------------------------------------------------------------

option (B) \frac{1}{3} 3^{n-1} which we can also write as

\frac{3^{n-1}}{3}  = \frac{3^{n-1}}{3^{1}}  = 3^{n-1-1}  = 3^{n-2}

we subtract exponents when dividing same bases so we subtracted exponent 1 from n-1 and finally got 3^{n-2}

so option (c) matches and is right answer

---------------------------------------------------------------------------------

option (D) 3\frac{1}{2}^{n-1} doesnt match to 3^{n-2}

so its incorrect

7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Bogdan [553]

The radical expressions and their corresponding expression in rational exponent form are

972^\frac 15 = 3\sqrt[5]{4}, 448^\frac 13 = 4\sqrt[3]{7}, 3528^\frac 12 = 42 \sqrt 2 and 4050^\frac 14 = 3\sqrt[4]{50}

<h3>How to match the tiles?</h3>

We start by evaluating each expression as follows:

972^\frac 15

Expand 972

972^\frac 15 = (243 * 3)^\frac 15

Take the 5th root of 243

972^\frac 15 = 3* (4)^\frac 15

Rewrite as:

972^\frac 15 = 3\sqrt[5]{4}

Next, we have:

448^\frac 13

Expand 448

448^\frac 13 = (64 * 7)^\frac 13

Take the 3rd root of 64

448^\frac 13 = 4 * (7)^\frac 13

Rewrite as:

448^\frac 13 = 4\sqrt[3]{7}

Next, we have:

3528^\frac 12

Expand 3528

3528^\frac 12 = (1764 * 2)^\frac 12

Take the square root of 1764

3528^\frac 12 = 42 * (2)^\frac 12

Rewrite as:

3528^\frac 12 = 42 \sqrt 2

Lastly, we have:

4050^\frac 14

Expand 4050

4050^\frac 14 = (81 * 50)^\frac 14

Take the 4th root of 81

4050^\frac 14 = 3 (50)^\frac 14

Rewrite as:

4050^\frac 14 = 3\sqrt[4]{50}

Read more about radical expressions at:

brainly.com/question/8952483

#SPJ1

5 0
2 years ago
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