Pleaseeeee helppppp!!!!! I have to turn this in...!!!

if you and your friend went swimming for 10 hours, then came back because they forgot something, then swam for 11 hours, how man

N76 [4]

Answer:

21 hours

Step-by-step explanation:

You and your friend swam for 10 hours then took a break then swam for 11 so 10+11=21 so you and your friend swam for 21 hours all together.

7 0

3 years ago

Joe works as a busboy making $7 per hour and as a theater usher making $9 per hour. Let b be the number of hours he works as a b

Vilka [71]

Answer:

The inequality describing the situation is:

$7b+9u>1500$

Step-by-step explanation:

Joe works as a busboy at the rate of = $7 per hour

Let the number of hours he works as a bus boy this month be = $b$ hours

∴ Amount Joe would make this month working as a busboy = $\$7\times b=\$7b$

Joe works as a theater usher at the rate of = $9 per hour

Let the number of hours he works as a theater usher this month be = $u$ hours

∴ Amount Joe would make this month working as a theater usher = $\$9\times u=\$9u$

Total amount Joe would make this month = $\$(7b+9u)$

His goal is earn more than $1500 this month.

∴ The situation can be represented in the following inequality:

$7b+9u>1500$

6 0

3 years ago

What are the missing side lengths in triangle PQR? And how did you find that answer pleaseee helppp!!

Zielflug [23.3K]

6sqrt2 for both since there equivalent

6 0

3 years ago

Ms. MacDonald raises rabbits. She starts with 5 rabbits. After a few months, she counts 5 times as many rabbits. The next time s

tiny-mole [99]

Answer:

C

Step-by-step explanation:

5 ^ 5 ^ 5 = 125

6 0

3 years ago

Read 2 more answers

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago