Question

THIS IS ALGEBRA 2 CAN ANYONE SOLVE IT FOR ME?

Answer 1

Answer:

(a)  128 ft

(b)  4 s

(c)  Vertex:  (1, 144)

Step-by-step explanation:

Given information:

• h(t) = height in feet
• t = time in seconds after the launch

Part (a)

The height of the projectile at launch is the value of h(t) when t = 0 (the y-intercept).

Therefore, from inspection of the graph, the y-intercept is (0, 128).

So the height of the projectile at launch is 128 ft.

Part (b)

The length of time it took for the projectile to land is the time from the beginning (when t = 0) to when the height is 0 (the x-intercept).  

From inspection of the graph, the x-intercept is (4, 0)

So the length of time it took for the projectile to land is 4 s.

Part (c)

The vertex is the turning point (minimum/maximum point).

Therefore, from inspection of the graph, the vertex is (1, 144).

The vertex represents the time and height at which the projectile was at its maximum.  So at the time of 1 second, the projectile was at its maximum height of 144 ft.