All categories

3 years ago

Бу — 7 = 7 3х — 8y = — 31

Mathematics

2 answers:

gulaghasi [49]3 years ago

7 0

Answer:

I hope this helps!!!!!

grin007 [14]3 years ago

6 0

Answer:

creo que es X= 13 , Y= -1

Step-by-step explanation:

3*(6y-7)-8y=-31

18y-21-8y=-31

10y=-10

y=(-1)

6*-1-7= x ----> X=13

You might be interested in

Genber wiil evaluate an 8th degree polynomial in x at x=10 using the remainder theorem and synthetic division.how many coefficie

lisabon 2012 [21]

An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.

x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.

Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉

The first few lines of the synthetic division are

10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)

-----------------------------------------
a₁

Answer:
The first row has 9 coefficients.

8 0

3 years ago

Is 9/3 a whole number

Liono4ka [1.6K]

Yes! 3x3= 9. Therefore, 3 goes into nine 3 times. So the whole number would be 3.

6 0

3 years ago

Read 2 more answers

Help d-7 < 12; d = 19

kompoz [17]

Answer:

12 ≮ 12

False

Step-by-step explanation:

19 − 7 < 12

12 ≮ 12 (<--- line through the less than sign)

False

(I'm not 100% sure)

3 0

1 year ago

Read 2 more answers

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

What is the measure of the central angle of a circle with radius 15 ft that intercepts a 10 ft arc?

olga2289 [7]

L=10ft
R=15ft
We have to find theta

$\Large{\underline{\sf Solution:-}}$

$\\ \sf\dashrightarrow L=\dfrac{\Theta}{180}\times \pi r$

$\\ \sf\dashrightarrow 10=\dfrac{\Theta}{180}\times 3.14\times 15$

$\\ \sf\dashrightarrow 10=\dfrac{\Theta}{180}\times 47.1$

$\\ \sf\dashrightarrow \Theta=\dfrac{10(180)}{47.1}$

$\\ \sf\dashrightarrow \Theta=\dfrac{1800}{47.1}$

$\\ \sf\dashrightarrow \Theta=38.2°$

5 0

2 years ago