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dalvyx [7]
3 years ago
13

PLEASE HELP!!! I WILL GIVE 50 BRAINLIST! ​

Mathematics
2 answers:
marin [14]3 years ago
3 0

Answer:

what are  supposed to do with these Like how do u want me to answer

Step-by-step explanation:

Mazyrski [523]3 years ago
3 0
What are you wanting us to do ??
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Please help me!!!! I don’t understand
ololo11 [35]

Answer:

<h2>m∠EFG = 126°</h2><h2>m∠GFH = 54°</h2>

Step-by-step explanation:

If ∠EFG and ∠GFH are a linear pair, then m∠EFG + m∠GFH = 180°

(look at the picture).

We have

m∠EFG = 5n + 16

m∠GFH = 2n + 10

Substitute:

(5n + 16) + (2n + 10) = 180             <em>combine like terms</em>

(5n + 2n) + (16 + 10) = 180

7n + 26 = 180            <em>subtract 26 from both sides</em>

7n + 26 - 26 = 180 - 26

7n = 154         <em>divide both sides by 7</em>

7n/7 = 154/7

n = 22

Insert the value of n into expressions that specify angle measures:

m∠EFG = 5n + 16 → m∠EFG = 5(22) + 16 = 110 + 16 = 126°

m∠GFH = 2n + 10 → m∠GFH = 2(22) + 10 = 44 + 10 = 54°

8 0
3 years ago
Which choice is irrational?
polet [3.4K]

Answer:

√18

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help pls itS BEEN 2 HOURS LUV U &lt;3
nataly862011 [7]

Step-by-step explanation:

Hey there!

The equation of a circle which passes through any point having centre (h,k) is;

( {x - h)}^{2}  + ( {y - k)}^{2}  =  {r}^{2}

In first blank ( x-_ ) keep "-2". In second blank (y - _ ) keep "4" and in last blank ( _ ) keep "36".

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
PLZ HELP ASAP MARKIN BRAINIEST !!!
zzz [600]
Put a dot on -7 and -1 so the slope is 3 over 2x for the first inequality and the y is -1 do rise over run for each the slope for second is 1 over 1 put a dot for both on y axis (:
3 0
4 years ago
A home security system is designed to have a 99% reliability rate. Suppose that nine homes equipped with this system experience
bulgar [2K]

Answer:

a) P(X \geq 1) = 1-P(X

P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}

And replacing we got:

P(X \geq 1) =1 -1x10^{-18} \approx 1

b) P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355

P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And adding we got:

P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992

c) P(X \leq 8) =1 -P(X>8) = 1-P(X=9)

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And replacing we got:

P(X \leq 8)= 1-0.913517=0.086483

Step-by-step explanation:

Let X the random variable of interest "numebr of times that an alarm is triggered", on this case we now that:

X \sim Binom(n=9, p=0.99)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

We want to find this probability:

P(X \geq 1) = 1-P(X

P(X=0)=(9C0)(0.99)^0 (1-0.99)^{9-0}=1x10^{-18}

And replacing we got:

P(X \geq 1) =1 -1x10^{-18} \approx 1

Part b

P(X \geq 7)= P(X=7) +P(X=8)+ P(X=9)

P(X=7)=(9C7)(0.99)^7 (1-0.99)^{9-7}=0.003355

P(X=8)=(9C8)(0.99)^8 (1-0.99)^{9-8}=0.083047

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And adding we got:

P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992

Part c

P(X \leq 8) =1 -P(X>8) = 1-P(X=9)

P(X=9)=(9C9)(0.99)^9 (1-0.99)^{9-9}=0.913517

And replacing we got:

P(X \leq 8)= 1-0.913517=0.086483

4 0
3 years ago
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