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3 years ago

Select the correct answer from each drop-down menu.

Mathematics

1 answer:

Elodia [21]3 years ago

8 0

Answer:

The left end approaches to + Infinite being an exponential function, and the right end to 0

Step-by-step explanation:

we have to remember the exponential function, the best way to find the answer is plotting the graph or arranging a table of values.

As you can see in the attached graph the y axis gets closer and closer to 0 as it moves forward in the x axis, and as it moves to the left the y axis starts increasing rapidly.

Also you got to keep in mind the way that functions behave in terms of the sign of its variable. for example the 10 in this equation only makes the curve to get wider, but if you change the sign to minus, the answer would be different.

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Find the value of x. Then find the measure of each labeled angle

Artyom0805 [142]

Step-by-step explanation:

Question 10 :

3x + 6 = 4x – 12 ( reason: corresponding angles due to parallel lines)

simplify and get x, thus x = 18

to find 3x + 6 or 4x - 12(which is both the same),

3(18) + 6 = 60° , 4(18) - 12 = 60°

Question 11:

2x + 24 + x = 180 ( reason: interior angles due to parallel lines)

simplify again to get x, you will get x = 52

then find the individual by subbing in the value of x into the equation.

so 2x + 24 = 2(52)+24 = 128° and x = 52°

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2 years ago

que ecuación se podria usar para encontrar la circunferencia en pies de un circulo con un radio de 7 pies?

slamgirl [31]

Answer:

Tu respuesta

Step-by-step explanation:

1.) https://www.montereyinstitute.org/courses/DevelopmentalMath/TEXTGROUP-1-8_RESOURCE/U07_L2_T3_text_final_es.html

7 0

2 years ago

. The estimate regression equation for a model involving two independent variables and 10 observations follows.y = 29.1270 + 0.5

beks73 [17]

Answer:

b) y = 289.815 when $x_1 = 180 \text{ and } x_2 = 310$

Step-by-step explanation:

We are given the following information in the question:

$y = 29.1270 + 0.5906x_1 + 0.4980x_2$

where y is the dependent variable,

$x_1, x_2$ are the independent variable.

The multiple regression equation is of the form:

$y = b_0 + b_1x_1 + b_2x_2$

where,

$b_0$ : is the intercept of the equation and is the value of dependent variable when all the independent variable are zero.

$b_1$ : It is the slope coefficient of the independent variable $x_1$ .

$b_2$ : It is the slope coefficient of the independent variable $x_2$ .

The regression coefficient in multiple regression is the slope of the linear relationship between the dependent and the part of a predictor variable that is independent of all other predictor variables.

Comparing the equations, we get:

$b_1 = 0.5906\\b_2 = 0.4980$

This means holding $x_2$ constant, a change of one in $x_1$ is associated with a change of 0.5906 in the dependent variable.

This means holding $x_1$ constant, a change of 1 in $x_2$ is associated with a change of 0.4980 in the dependent variable.

b) We have to estimate the value of y

$y = 29.1270 + 0.5906(180) + 0.4980(310) = 289.815$

3 0

2 years ago

Find the value of h .

MariettaO [177]

Answer:

xowowo2o2oeoddoxxocckckcll

6 0

2 years ago

Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.

Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If $x + \dfrac{1}{x}$ is an integer

∴ $\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

$x + \dfrac{1}{x}$

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}$

By simplification of the cube of the given integer expressions, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )$

Therefore, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}$

By rearranging, we get;

$x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )$

Given that $x + \dfrac{1}{x}$ is an integer, from the closure property, the product of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3$ is an integer and $3\cdot \left (x + \dfrac{1}{x} \right )$ is also an integer

Similarly the sum of two integers is always an integer, we have;

$\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

$\therefore x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right )$ is an integer

From which we have;

$x^3 + \dfrac{1}{x^3}$ is an integer.

4 0

3 years ago