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MatroZZZ [7]
3 years ago
5

The ordered pair(5,-3) is a solution to which of the following inequalities?

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

A plumber worked 26 hours a week for half a year. If his hourly wage was $40, how much did he earn during this time period?

<span> <span>A.</span>$1040</span><span> <span>B.</span>$27,040</span><span> <span>C.</span>$54,080</span><span> <span>D.</span><span>$520</span></span>
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?÷(−7)=(−4) what is the missing number
Hunter-Best [27]

Answer:

The answer is 28.

Step-by-step explanation:

To find the solution, you must multiply the other two numbers together to find the original number that is divided.

-7 * -4 = 28 Answer

28/-7 = -4

Hope this helps!

3 0
3 years ago
Read 2 more answers
There are 20 members of a basketball team.
Lisa [10]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Consider the graph of the function f(x) = 25
trasher [3.6K]

Considering it's horizontal asymptote, the statement describes a key feature of function g(x) = 2f(x) is given by:

Horizontal asymptote at y = 0.

<h3>What are the horizontal asymptotes of a function?</h3>

They are the limits of the function as x goes to negative and positive infinity, as long as these values are not infinity.

Researching this problem on the internet, the functions are given as follows:

  • f(x) = 2^x.
  • g(x) = 2f(x) = 2(2)^x

The limits are given as follows:

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 2(2)^x = \frac{2}{2^{\infty}} = 0

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 2(2)^x = 2(2)^{\infty} = \infty

Hence, the correct statement is:

Horizontal asymptote at y = 0.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

3 0
1 year ago
Use the disruptive property in order to multiply 5(b + 8)
Vikki [24]

Answer:

5b+40

Step-by-step explanation:

distributive property

8 0
3 years ago
Can someone help me with this? Plz.<br><br> Solve the quadratic equation 2x^2-4x-1=0
Mila [183]
You have to use the quadratic formula to solve this. The zeros of this quadratic are 2 + sqrt2/2 and 2 - sqrt2/2, which in "real" numbers is 1.707 and .2928
6 0
2 years ago
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