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prisoha [69]
3 years ago
15

5. Claustrophobia is an example of a(n)

Mathematics
2 answers:
nalin [4]3 years ago
7 0

The answer is B. Anxiety disorder

bekas [8.4K]3 years ago
4 0

Answer:

Claustrophobia is an example of a anxiety disorder

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Simplify 2a + 14 - 5a - 7 + 8a​
Dmitry_Shevchenko [17]

Step-by-step explanation:

2a -5a +8a.

2a +8a -5a

10a -5a = 5a

14-7=7

<em>Answer=5a+7</em>

8 0
3 years ago
Read 2 more answers
Keep the ratio simple.<br> 3/5 : 2/5
fredd [130]

Answer:

3:2

Step-by-step explanation:

I am assuming this means convert to whole numbers

3/5:2/5 is 6/10:4/10

6/10:4/10 is 0.6:0.4

0.6:0.4 is 6:4

6:4 is 3:2

8 0
1 year ago
Read 2 more answers
Use absolute value notation to represent the distance between x and 8 is no more than 4
ivanzaharov [21]
The distance: use absolute value
Between x and 8: x-8

The distance between x and 8: | x-8 |

“is no more than” means it can be that or be less than that, so use ≤

The distance between x and 8 is no more than 4

| x-8 | ≤ 4
3 0
2 years ago
( I know the answers I just don't get why)
Over [174]
1)

neverminding how many grams or liters...or whatever unit for now
we know one bag of grass covered 1/6 of the lawn, "a whole" or 1, is 6/6
if 1 bag covers 1/6, to cover 6/6 is just 1/6 +1/6 +1/6 +1/6 +1/6 +1/6 , or 6 bags

2)

one can was enough for 1/4 of the sprayer, a full sprayer is 1 whole or 4/4, so 1/4 + 1/4 + 1/4 + 1/4  or 4 cans

3)

one potato gives enough for 1/3 for a lighbulb, again, 1 whole is 3/3, so 1/3 +1/3 +1/3 , so 3 potatoes
8 0
3 years ago
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
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