Answer:
custom-built to address the specific requirements of a business
Explanation:
Answer: Contact the manufacturer and asks for another filter driver device.
Explanation:This issue can occur if a non-Microsoft program installed on your computer uses an outdated kernel-mode filter driver. And it can be that kernel-mode filter driver may be outdated.
Answer:
18
Explanation:
If you take the formula, and you substitute the values of the variables, it will be:
10 * 2 - 10 / 5
Then if you remember the order of math operations, it will be:
(10 * 2) - (10 / 5)
Which reduces to:
20 - 2 = 18
Answer:
def occurencesOfWords(words,freq):
frequency_dictionary={}
matched_frequency_words=[]
for i in range(len(words)):
counter=1
a=words[i].lower()
for j in range(len(words)):
if(i==j):
continue
b=words[j].lower()
if(a==b):
counter+=1
frequency_dictionary[words[i]]=counter
for key in frequency_dictionary:
if(frequency_dictionary[key]==freq):
matched_frequency_words.append(key)
return matched_frequency_words
if __name__=='__main__':
user_input=input()
freq=int(input())
words=user_input.split(" ");
required_words=occurencesOfWords(words,freq)
for s in required_words:
print(s)
Explanation:
- Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string
.
- matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
- Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
- Increment the counter variable, if two string are equal.
- Loop through the frequency_dictionary to get the matching frequency strings
.
- Finally test the program inside the main function.
