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4 years ago

Why do polar compounds tend to have higher melting boiling points than nonpolar compounds?

1 answer:

3 0

Polar compounds have permanent dipole-dipole interactions as well as induced dipole-dipole interactions. As there are more stronger intermolecular forces, it takes more energy for these forces to be broken and therefore higher heat to melt and boil them

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Why does platinum metal make a good catalytic surface for reactant molecules?

d1i1m1o1n [39]

Answer:

it holds reactant molecules in a good position for then to react

3 0

3 years ago

If the theoretical yield of the reaction below corresponds to 25.3 g and the percent yield of the reaction is known to be reprod

maksim [4K]

Answer:

Actual yield = 20.52 g

Explanation:

Given data:

Theoretical yield = 25.3 g

Percentage yield = 81.1 %

Actual yield = ?

Solution:

Formula:

Percentage yield = Actual yield /theoretical yield × 100

81.1 % /100 = Actual yield / 25.3 g

0.811 = Actual yield / 25.3 g

Actual yield = 0.811 × 25.3 g

Actual yield = 20.52 g

3 0

3 years ago

Why Sodium and phosphorus are in the same period, but they have different atomic radii?

Marianna [84]

Answer:

Because sodium is on the left side of the PT and phosporus is on the right side. And atomis radius decreases from left to right.

Explanation:

4 0

3 years ago

Sir J.J. Thompson discovered the electron in 1897. How did Thompson explain the overall neutral charge of the atom?

navik [9.2K]

your answer is C you're welcome

4 0

4 years ago

A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?

Elodia [21]

Answer: The mole fraction of barium chloride in the solution is 0.024

Explanation:

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

$1.230g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.230g/mL\times 1000mL)=1230g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

$1.30mol=\frac{\text{Mass of barium chloride}}{208g/mol}\\\\\text{Mass of barium chloride}=(1.30mol\times 208g/mol)=270.4g$

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

Calculating the moles of water:

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{959.6g}{18g/mol}\\\\\text{Moles of water}=53.31mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For barium chloride:

$\chi_{\text{(barium chloride)}}=\frac{n_{\text{(barium chloride)}}}{n_{\text{(water)}}+n_{\text{(barium chloride)}}}$

$\chi_{\text{(barium chloride)}}=\frac{1.30}{1.30+53.31}\\\\\chi_{\text{(barium chloride)}}=0.024$

Hence, the mole fraction of barium chloride in the solution is 0.024

6 0

4 years ago