Answer: 0.0014 atm
Explanation:
Given that,
Original pressure of air (P1) = 1.08 atm
Original volume of air (T1) = 145mL
[Convert 145mL to liters
If 1000mL = 1l
145mL = 145/1000 = 0.145L]
New volume of air (V2) = 111L
New pressure of air (P2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P2V2
1.08 atm x 0.145L = P2 x 111L
0.1566 atm•L = 111L•P2
Divide both sides by 111L
0.1566 atm•L/111L = 111L•P2/111L
0.0014 atm = P2
Thus, the new pressure of air when the volume is decreased to 111 L is 0.0014 atm
Tincture of iodine has antiseptic properties and is made by dissolving iodine crystals in alcohol.
<h3>What are antiseptics?</h3>
Antiseptics are substance which prevent or stops the growth of microorganisms.
Microorganisms have been known to cause diseases, therefore the application of antiseptics are useful to prevent diseases.
An example of an antiseptic is tincture of iodine.
Tincture of iodine is prepared by dissolving iodine crystals in alcohol.
In conclusion, antiseptics are useful in the prevention of diseases by microorganism. An example of an antiseptic is tincture of iodine.
Learn more about tincture of iodine at: brainly.com/question/3209701
#SPJ1
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Density = 11g/cm³, volume = 2cm³. What is the mass ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
We know,

So, Mass = 11g/cm³ × 2cm³
Mass = 22 g
<h3>The mass is <u>2</u><u>2</u><u> </u><u>g</u>. [Answer]</h3>
My guess would be "B) they were produced by volcanoes" because hawaii has a bunch of volcanoes and volcanoes can produce extra land. While the other answers wouldn't make sense. Definitely B.
Answer:
a) The wavelength is around 33.8 nm = 3.38*10⁻¹ nm
b) Ultraviolet
Explanation:
a) The energy (E) of a photon is related to its wavelength (λ) by the Planck's equation:

where h = Planck's constant = 6.626*10^-34 Js
c = speed of light = 3*10^8 m/s
E = 3.55*10^6 J/mol
The energy in terms of J/photon is:

Based on eq(1)
\lambda = h\frac{c}{E}=6.626*10^{-34}Js*\frac{3*10^{8}m/s}{5.89*10^{-18}J}=3.38*10^{-8}m
The wavelength is around 33.8 nm = 3.38*10⁻¹ nm
b) In the electromagnetic spectrum the ultraviolet range extends from 390 nm-8.82 nm
The calculated wavelength of 33.8 nm should fall in the UV range.