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zhenek [66]
3 years ago
9

WHAT IS AC WILL MARK BRAINLIEST

Mathematics
1 answer:
daser333 [38]3 years ago
3 0
I think the answer is 3.5
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AA'B'C'is a reflection of AABC over the y-axis. What is the length of A'C'?
yKpoI14uk [10]

Answer:

<em>(A). 6 units</em>

Step-by-step explanation:

6 0
3 years ago
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The radius, R, of a sphere, is 6.3cm. Calculate the sphere's volume, V.
sleet_krkn [62]

Answer:

V = 1046.9

Step-by-step explanation:

The equation for volume is (4/3)pi r^3

substitute 3.14 in for pi and 6.3 in for r so (4/3)*3.14*6.3^3

6 0
2 years ago
Solve the equation 3x+x²=-7. Does the number of solutions match the information provided by the discriminant? Explain
MA_775_DIABLO [31]

Answer:

-\frac{3}{2}+\frac{\sqrt{19}i}{2} and -\frac{3}{2}-\frac{\sqrt{19}i}{2}

Step-by-step explanation:

3x+x^2=-7\\\Rightarrow x^2+3x+7=0

Discriminant

D=b^2-4ac\\\Rightarrow D=3^2-4\times 7\times 1\\\Rightarrow D=-19

If the discriminant is a negative number then the roots of the equation are imaginary

x=\frac{-b\pm \sqrtD}{2a}\\\Rightarrow x=\frac{-3\pm \sqrt{-19}}{2\times 1}\\\Rightarrow x=-\frac{3}{2}\pm \frac{\sqrt{19}i}{2}\\\Rightarrow x=-\frac{3}{2}+\frac{\sqrt{19}i}{2}, x=-\frac{3}{2}-\frac{\sqrt{19}i}{2}

So, the two solutions are -\frac{3}{2}+\frac{\sqrt{19}i}{2} and -\frac{3}{2}-\frac{\sqrt{19}i}{2}

3 0
3 years ago
I need help ASAP. The assignment is due at 11:59
Oksanka [162]

Answer:

its answer is 75 i guess

5 0
3 years ago
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A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.
scZoUnD [109]

Answer:

Probability of getting doubles = 1/4

Step-by-step explanation:

Given - A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.

To find - Using a sample space diagram, find the probability of getting a double.

Proof -

Given that,

A four-sided spinner is spin twice.

So,

The Sample Space becomes

S = { (1, 1), (1, 2), (1, 3), (1, 4)

       (2, 1), (2, 2), (2, 3), (2, 4)

       (3, 1), (3, 2), (3, 3), (3, 4)

       (4, 1), (4, 2), (4, 3), (4, 4) }

So,

n(S) = 16

Now,

Let A is the event Getting a double, So,

A = { (1, 1), (2, 2), (3, 3), (4, 4) }

and

n(A) = 4

So,

The Probability of getting doubles = n(A) ÷ n(S)

                                                         = 4 ÷ 16

                                                         = 1/4

∴ we get

Probability of getting doubles = 1/4

6 0
3 years ago
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