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Vlad1618 [11]
3 years ago
12

Need The Answer Plz And Thank You!! I’m Failing

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0

Angle BCA

Step-by-step explanation:

You can see this due to the angle having the name amount of congruent angle marks.

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Please help I'm kinda confused-<br>​
ozzi
<h3>Answer:  0</h3>

=====================================================

Explanation:

The term "variant" means "it changes" or "it moves location".

So "invariant" means it stays fixed in place.

The translation vector \binom{1}{3} is the same as writing the rule (x,y) \to (x+1,y+3). It says to shift every (x,y) point 1 unit to the right and 3 units up. The key to this is the "every". There isn't a point left out that the translation doesn't touch. No points stay fixed in place. <u>There are no invariant points</u>.

In contrast, if we were to do a dilation, then the invariant point is the center of the dilation. Everything either shrinks or enlarges with respect to this fixed center point. Another example would be a rotation where the center of rotation stays fixed. Unfortunately, translations do not have this property of having an invariant fixed point.

5 0
2 years ago
Help me with 8-9 if you get it right i would give you brain list have a good day!
ad-work [718]

Answer:

i cant help with that cause i have no way of drawing

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A=(2 3)<br> (-1 4)<br><br> Calculate A^2-6A+11I
disa [49]

Answer:

A² - 6A + 11 I = \left[\begin{array}{ccc}0&0\\0&0\end{array}\right]

Step-by-step explanation:

Given the matrix

A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]

Calculate A² - 6A + 11 I

A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]

6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]

11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]

∴ A² - 6A + 11 I = \left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]

8 0
3 years ago
At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res
Degger [83]

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

3 0
3 years ago
The sphere is _____ cubic centimeters bigger than the cube. (Round to the nearest cubic centimeter.)
Misha Larkins [42]

ANSWER

The sphere is 10762 cubic centimeters bigger than the cube.

EXPLANATION

We want to find the difference in the volumes of the sphere and the cube.

To do this, we have to find the volumes of the sphere and cube and subtract that of the cube from the sphere.

The volume of a sphere is given as:

V=\frac{4}{3}\pi r^3

where r = radius

The radius of the sphere is 15 centimeters. Therefore, the volume of the sphere is:

\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot15^3 \\ V\approx14137\operatorname{cm}^3 \end{gathered}

The volume of a cube is given as:

V=s^3

where s = length of the side

The length of the side of the cube is 15 centimeters. Therefore, the volume of the cube is:

\begin{gathered} V=15^3 \\ V=3375\operatorname{cm}^3 \end{gathered}

Therefore, the difference in the volumes of the sphere and cube is:

\begin{gathered} V_d=V_s-V_c \\ V_d=14137-3375 \\ V_d=10762\operatorname{cm}^3 \end{gathered}

Therefore, the sphere is 10762 cubic centimeters bigger than the cube.

6 0
1 year ago
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