Answer: 137π
The usual formula for a circle centered at (a,b), with radius r,
(x - a)² + (y - b)² = r²
The area of the circle is πr², so 137π
-8
On the number line if you are at positive 8 and add -8 you will lose 8 and get zero! Hope this helps!
Well, you have to be given an interval. That is not an interval.
You should be given something like

If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3
Answer:
B
Step-by-step explanation:
Answer:

Step-by-step explanation:
Hi there!

To get rid of the fraction
, multiply both sides of the equation by 3 (the denominator):

To get rid of the fraction
, multiply both sides of the equation by 5 (the denominator):

I hope this helps!