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Andrej [43]
3 years ago
10

What is the y-intercept of the linear equation y=5x+7

Mathematics
2 answers:
natka813 [3]3 years ago
5 0
The y-intercept would be 7.
bagirrra123 [75]3 years ago
3 0
I think it's 7, let me check.
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Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20​
Gemiola [76]
<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

  • To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }

<h2>_____________________________________</h2>

Here:-

\bold \blue{leg \: 1 = 48} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\ \bold  \blue{ leg2 = 20} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \bold\blue{hypotenuse = 52}

Putting values:-

{48}^{2}  +  {20}^{2}  = {52}^{2}   \:  \:  \:  \:  \:  \: \\  \\ 2304 + 400 = 2704 \\  \\ 2704 = 2704 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<h2>_____________________________________</h2>
4 0
2 years ago
i) Baraka bought ksh.20,000 worth of shares of a company each month. During the first three months, he bought the shares at a pr
Sladkaya [172]

The average price paid by him for the shares after 3 months is ksh. 163.33

<h3>Average</h3>

  • Total value of shares bought = ksh.20,000

  • Amount of shares bought in the first three months = ksh.120, ksh.160 and ksh.210

Average price paid for the shares after 3 months

= (120 + 160 + 210) / 3

= 490 / 3

= 163.333333333333

Approximately,

ksh. 163.33

Learn more about average:

brainly.com/question/20118982

#SPJ1

4 0
2 years ago
Find the number that makes the 2 fractions equivalent 3/8=9/?
Lorico [155]

Answer:

24

Step-by-step explanation:

The numerator of the equivalent fraction of 3/8 is 9. From this, we can see that the common factor that is being multiplied is 3. So the denominator, 8, has to be multiplied by 3 as well which gives you 24. 9/24 is an equivalent fraction of 3/8

6 0
3 years ago
Read 2 more answers
Which exponential function is represented by the graph?
Anna [14]

Answer:

Step-by-step explanation:

Let's solve this using our formula for exponential functions:

y=a(b)^x where a is the initial value and b is the growth/decay rate. We will fill that equation in with 2 of the coordinates on the graph and come up with the values for both a and b. (0, 3) and (1, 6):

3=a(b)^0. Anything raised to the power of 0 is 1, so that means that

a = 3. We will use that value along with the x and y from the second coordinate to solve for b:

6=3(b)^1. b to the first is just b, so our equation is

6 = 3b and

b = 2.

Our equation then is

y=3(2)^x, the third choice down.

8 0
3 years ago
Use substitution to write an equivalent quadiatic equation<br> ( 3x^2)^2+7(3x +2) -8=0
mezya [45]

Answer:

9x^4+21x+6=0

Step-by-step explanation:

( 3x^2)^2+7(3x +2) -8=0

((3^2)*(x^2)^2)+(7*3x)+(7*2)-8=0

9(x^4)+21x+14-8=0

9x^4+21x+6=0

7 0
3 years ago
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