Question

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.​

Answer 1

Required number is 17.

Justification:

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively.

Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

• 398 - 7 = 391
• 436 - 11 = 425
• 542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

Hence, the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.

Answer 2

Answer:

17

Step-by-step explanation:

398-7 =391

436-11 =425

542 -15=527

Find their G.C.D which is 17

Answer =17