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3 years ago

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.

Mathematics

2 answers:

marin [14]3 years ago

8 0

Required number is 17.

<h3>Justification:</h3>

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively.

Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

398 - 7 = 391
436 - 11 = 425
542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

Hence, the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.

s344n2d4d5 [400]3 years ago

4 0

Answer:

Step-by-step explanation:

398-7 =391

436-11 =425

542 -15=527

Find their G.C.D which is 17

Answer =17

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Read 2 more answers

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.​

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.