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klasskru [66]
3 years ago
14

Find the largest positive integer that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively.​

Mathematics
2 answers:
marin [14]3 years ago
8 0

Required number is 17.

<h3>Justification:</h3>

<u>We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively</u>.

Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

  • 398 - 7 = 391
  • 436 - 11 = 425
  • 542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

<u>Hence, the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17</u>.

s344n2d4d5 [400]3 years ago
4 0

Answer:

17

Step-by-step explanation:

398-7 =391

436-11 =425

542 -15=527

Find their G.C.D which is 17

Answer =17

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Answer:

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Step-by-step explanation:

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Then:

(5/7)r + 40 + (3/4)r - 118 = r

The LCD of the fractions 5/7 and 3/4 is 28.  We thus have:

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3 years ago
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Answer:

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This is the determinant of the matrix with the x-coefficients replaced by the constants.

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This is the determinant of the matrix with the y-coefficients replaced by the constants.

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_____

This problem didn't ask, but the solution is ...

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Step-by-step explanation:

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Answer:

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