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lisov135 [29]
3 years ago
8

A bicyclist covered 5/7 of his route and an additional 40 miles. He has yet to cover 118 miles less than 0.75 of his route. How

long is his route in miles?
Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

6 miles

Step-by-step explanation:

Let the route length be r.  The distance the cyclist has already covered is then (5/7)r + 40.  This plus 0.75r - 118 must = r, the length of the entire route.

Then:

(5/7)r + 40 + (3/4)r - 118 = r

The LCD of the fractions 5/7 and 3/4 is 28.  We thus have:

(20/28)r + 40 + (21/28)r - 118 = r, or

(41/28)r - 78 = (28/28)r

Combining the r terms, we get 13r = 78, and so r = 78/13 = 6.

The cyclist's bike route is 6 miles long.

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
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Answer:

a) Binomial distribution B(n=12,p=0.01)

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Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

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P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

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c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

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