Answer:there are 24,000 sears in section A, 14,600 in section B and 19,400 in section C.
Step-by-step explanation:
Step 1
let the number of seats in section B = x
and the number of seats in section C.=y
Given that the number of seats in section A is the sum of seats in sections B and C, we can then say A =x + y
From the given question, We have that
seatsA + seatsB + seatsC = 48,000 which also equals
(x+y) + x + y = 48,000
2x + 2y = $48,000
2(x+y) = 48,000
x + y = 48,000/2 =24,000 which also equals
B+C =24,000
Now the number of seats in section A =24,000 and the sum of seats in sections B and C is 24000.
We now have
B+C = 24,000------ eqn (1)
Also
since we already have the number of seats for Section A, We will find Section B and C
A +B+C =1,239,600,
$30 x 24,000 + 24B + 18C= 1,239,600
720,000 + 24B + 18C= 1,239,600
24B + 18C= 1,239,600-720,000
24B + 18C= 519,600--------- eqn 2
Step 2 We will now solve with the following equations
B+C = 24,000------ eqn (1)
24B + 18C= 519,600--------- eqn 2
Multiply eq(1) by 24 (both sides). Then subtract eq(2) from it:
24B + 24C = 576,000-------eqn (3)
24B+ 18C = 519,600-- ---eqn(4)
6C = 576,000- 519,600
6C=56,400
C= 9,400
TO get B.
B+C = 24,000
B= 24,000 - 9,400
B=14,600
Therefore, there are 24,000 sears in section A, 14,600 in section B and 19,400 in section C.
