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harkovskaia [24]

3 years ago

12

Given the figure below. What is the theorem or postulate that justifies triangle ABD congruent

1 answer:

Zina [86]3 years ago

7 0

Answer:

SAS is the answer in my opinion

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A line through the origin and (10,4) is showin in the standard (x,y) coordinate plane below. The acute angle between the line an

Snowcat [4.5K]

Answer:

$\cos\theta=\frac{10}{\sqrt{116}}$

Step-by-step explanation:

To solve this, we can imagine a line drawn directly down from the point (10,4) to the x-axis. This would make a right triangle with length 10 and height 4.

$\cos\theta$ is equal to the length of adjacent leg to the angle divided by the length of the hypotenuse of the triangle. From the picture, we can see the adjacent leg is 10.

We can use Pythagorean's Theorem to find the hypotenuse (let $c$ represent the length of the hypotenuse):

$10^2+4^2=c^2$

$100+16=c^2$

$116=c^2$

$c=\sqrt{116}$

Thus, we know the adjacent is 10, and the hypotenuse is $\sqrt{116}$ . This means $\cos\theta=\frac{10}{\sqrt{116}}$ .

Hope this helps!

5 0

3 years ago

Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

4 years ago

Triangle A′B′C′ is the image of triangle ABC after a dilation.

IceJOKER [234]

Answer:

3

Step-by-step explanation:

could the length of the first triangle to the length of the second triangle

7 0

2 years ago

What is the slope between points (4, 6) and (-2, 6).

olchik [2.2K]

I believe the answer is 0

6 0

3 years ago

What is 1+ 25372 +62719+ 82837?

Lynna [10]

Answer:

170929

Step-by-step explanation:

7 0

3 years ago

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