One can be 7/2 ...................
Answer:
A.)
H0: μ ≤ 31
H1: μ > 31
B.)
H0: μ ≥ 16
H1: μ < 16
C.)
Right tailed test
D.)
If Pvalue is less than or equal to α ; we reject the Null
Step-by-step explanation:
The significance level , α = 0.01
The Pvalue = 0.0264
The decision region :
Reject the null if :
Pvalue < α
0.0264 > 0.01
Since Pvalue is greater than α ; then, we fail to reject the Null ;
Then there is no significant evidence that the mean graduate age is more Than 31.
B.)
H0: μ ≥ 16
H1: μ < 16
Null Fluid contains 16
Alternative hypothesis, fluid contains less than 16
One sample t - test
C.)
Null hypothesis :
H0 : μ ≤ 12
. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.
Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12
d.)
If Pvalue is less than or equal to α ; we reject the Null.
The given variable is a continuous variable.
<h3>What is
continuous variable?</h3>
A quantitative variable can be either continuous or discrete depending on whether it is normally obtained through measurement or counting. A variable is continuous over a range of real values if it can take on any two specific real values and all other real values in between.
<h3>What is mercury thermometer?</h3>
In Amsterdam, physicist Daniel Gabriel Fahrenheit created the mercury thermometer, also known as a mercury-in-glass thermometer. It consists of a glass tube with a small diameter and a mercury bulb attached to it; the bulb contains far more mercury than the tube does.
<h3>According to the information:</h3>
A mercury thermometer was used to take the subject's temperature.
Because of the temperature:
- Not counting but measuring it.
- You can use a decimal number to represent its value.
- As a result, it is open to any value inside an interval.
- Temperature is therefore a continuous variable.
- The only format in which discrete values can be stated is as whole numbers.
so
Temperature is a continuous variable,
To know more about continuous variable visit:
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Answer:
Did you ever get the answer
Step-by-step explanation:
Answer:
82
Step-by-step explanation:
Evaluate 4 x^2 - 14 x + 4 where x = -3:
4 x^2 - 14 x + 4 = 4×(-3)^2 - -3×14 + 4
(-3)^2 = 9:
4×9 - 14 (-3) + 4
4×9 = 36:
36 - 14 (-3) + 4
-14 (-3) = 42:
36 + 42 + 4
| 1 |
| 4 | 2
| 3 | 6
+ | | 4
| 8 | 2:
Answer: 82