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2 years ago

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Mathematics

1 answer:

Lubov Fominskaja [6]2 years ago

8 0

Answer:

helllllllllllllllllllllllllllllp

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Alice stand at point A and looks at the top of a 17.8 m tree TB, such that her line of sight makes an angle 38° with the horizon

Nesterboy [21]

Answer:

Step-by-step explanation:

let the horizontal distance be x

(17.8-1.5)/x = tan 38

or x = 16.3/tan38

or x = 20.863

4 0

2 years ago

What makes b in the equation true 3/8 X 8/b

Gala2k [10]

$\frac{3}{8} * \frac{8}{b} = \frac{3}{1} * \frac{1}{b}$ (I crossed simplify)

Next cross multiply;

3b = 1

b = 1/3

To check if the statement is true just substitute the value of b in the equation;

3b = 1

3(1/3) = 1

1 = 1

8 0

3 years ago

If these two figures are similar what is the measure of the missing side length J?

Ray Of Light [21]

If the long side on both is 9ft and 3ft then 3•3 is 9 so for the short side you do the same. If the short side is 1ft and the other is "j" then it's 1•3 is 3.

1•3=3
Sorry if it's confusing the way I explained it.

3 0

2 years ago

How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$

7 0

3 years ago

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Kent multiplies both sides of the equation below by an expression. k+12/k=8 Then he moves all the terms to one side of the equal

BartSMP [9]

<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore,
k^2+12k-8k=0

Thus,
The equations he must solved now is k^2-8+12=0

3 0

2 years ago

Read 2 more answers