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3 years ago

10

PLEASE HELP APAP, WILL MARK BRAINLIEST WHEN POSSIBLE! The length of a rectangle is shown below:

2 answers:

Gennadij [26K]3 years ago

7 0

I think its the Fourth answer

prisoha [69]3 years ago

6 0

Im pretty sure the correct answer is the fourth one

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<img src="https://tex.z-dn.net/?f=5%20%2B%20%20%5Cfrac%7Bx%20-%202%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7Bx%20%2B%203%7D%7B8%7D%20" i

sammy [17]

First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
$24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )$
This will give you,
$120 + 8(x - 2) = 3(x + 3)$
Then just continue to simplify and isolate the variable.
$120 + 8x - 16 = 3x + 9$
$8x + 104 = 3x + 9$
$5x = - 95$
$x = - 19$

7 0

3 years ago

statuscvo [17]

Answer:

18ywjhtzk8ywbhuj

Step-by-step explanation:

ujzjtzjdjwjduxhxhwbsusuww

4 0

3 years ago

Check my answer? Please, no joking around guys.

WITCHER [35]

This is a right angle triangle
So we can use the tangent
tan x = 5/20
tan x= 0.25
x=tan^-1 (0.25)
x= 14.04 degrees
So yes you're correct

3 0

3 years ago

Read 2 more answers

Is this triangle congruent by

Alenkasestr [34]

Answer:

SAS

Step-by-step explanation:

8 0

3 years ago

The height h, in feet, of a ball that is released 4 feet above the ground with an initial velocity of 80 feet per second is a fu

gulaghasi [49]

Answer with Step-by-step explanation:

The height of the ball from the ground as a function of time is given by

$h(t)=-16t^2+80t+4$

The height of the ball at any instant of time can be found by putting the value of time 't' in the above relation as

Part a)

Height of ball after 2 seconds it is released is

$h(2)=-16\times 2^2+80\times 2+4=100feet$

Part b)

Height of ball after 4 seconds it is released is

$h(4)=-16\times 4^2+80\times 4+4=68feet$

4 0

4 years ago

Read 2 more answers