Answer:
<h3>i) Angle AOC is 95°
</h3><h3>Reason:- Angle AOC is equal to Angle DOB since they are Vertically Opposite Angles.
</h3>
<h3>
ii) Angle BOC is 85°
</h3><h3>Reason:- Angle AOC + Angle BOC - 180° (they lie in a straight line so they are a linear pair. Sum of the angles will be 180°)
</h3><h3>
Angle AOC is 95°, So:-
</h3><h3>
95° + Angle BOC = 180°
</h3><h3>
Angle BOC= 180° - 95°
</h3><h3>
Angle BOC = 85°
</h3><h3>
</h3><h3>iii) Angle DOE is 17°
</h3><h3>Reason:- Angle AOE+ Angle DOE+ Angle DOB = 180° (they lie in a straight line so they're a linear pair. Sum of the angles will be 180°)
</h3><h3>
So,
</h3><h3>
68° + Angle DOE+ 95° = 180°
</h3><h3>
163° + Angle DOE = 180°
</h3><h3>
Angle DOE= 180° - 163°
</h3><h3>
Angle DOE is 17°</h3>
Answer: -7744.
Step-by-step explanation: ...
I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A

: It looks like this in the calculator

× cos A=

(0.6489)
(

and cos cancels out)
A=

(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)