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s344n2d4d5 [400]
3 years ago
9

Help for all, will mark brainliest!!!!! :)

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

Number 4: Using Pythagoras Theorem,

\sqrt{30^2+40^2} =50

Number 5:

\sqrt{41^2-40^2}=9

3:

\sqrt{11^2+60^2} =61 It is a right triangle

4:

\sqrt{9^2+37^2} =38.09 Not a right triangle

For the last one:

\sqrt{(\sqrt{20^2+6^2})^2+6^2} =2\sqrt{118}

Rounded down (because the answer needs to be a whole number) is 21

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IF the sum of four times a number and four less than three times a number is seventeen what is the number
Virty [35]

Answer: 3

Step-by-step explanation: This equation can be written as 4x+3x-4=17

We can now solve.

Moving the 4 to the other side (adding) and we get 21.

Now we have 4x+3x. Adding like terms, we get 7x = 21. Now we divide by 7.

X = 3.

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Which numbers are composite numbers? Select all that are true
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49

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How do u do #10? Plz show on paper
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Reflection across the line y=x simply swaps the x and y coordinates.
K'(-2, -5), A'(1, -4), I'(-1, 0), J'(-4, -2)

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3 years ago
John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collectio
MrRissso [65]

The number of postage stamps in John’s collection is 27.

We have given that,

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps.

<h3>What is an elimination method?</h3>

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with the multiplication or division of coefficients of the variables.

Johan and Jonathan have the same number of stamps.

Let x be the Johan and Jonathan postal stamps.

Let y be the John postal stamps.

Two times Johan’s collection is eleven less than five times John’s collection.

2x = 5y - 11............(1)

Three times Jonathan’s collection is three less than seven times John’s collection.

3x = 7y - 3............(2)

Multiply equation 1 with 3

3(2x = 5y - 11)

⇒ 6x = 15y - 33.........(3)

Multiply equation 2 with 2

2(3x = 7y - 3)

⇒ 6x = 14y - 6.............(4)

Subtract equation 4 from equation 3

⇒ 6x - 6x = 15y - 33 - (14y - 6)

⇒ 0 = y - 27

⇒ y = 27

Hence, the number of postage stamps in John’s collection is 27.

Find more information about the elimination method here

brainly.com/question/13877817

#SPJ1

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