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nadya68 [22]
3 years ago
14

For the diagram shown, which angles are alternate interior angles?

Mathematics
1 answer:
Tanya [424]3 years ago
4 0

Answer:

∠3 and ∠5

Step-by-step explanation:

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What are the values of M and theta in the diagram below
Montano1993 [528]

Answer:

The correct answer is m=\frac{\sqrt{3} }{2} and θ = 30º.

Step-by-step explanation:

First, we must form a triangle whose hypotenuse is the radius r=1, its adjacent leg is m, its opposite leg is \frac{1}{2} and the angle is theta.

First, we calculate the angle with theta's breast:

sin (θ) = \frac{\frac{1}{2} }{H}

where H is the hypotenuse, in this case, the radio.

θ = sin^{-1} (\frac{\frac{1}{2} }{1})

θ = 30º

Now, we calculate the adjacent leg, which is equal to the x-coordinate of the point:

cos (θ) = \frac{m}{H}

m = cos 30º * H

m = \frac{\frac{\sqrt{3} }{2} }{1}

m = \frac{\sqrt{3} }{2}

Have a nice day!

3 0
3 years ago
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Simplify....... <br><br><br><br>-9-6c-j​
marin [14]

Answer: −6c−j−9

Step-by-step explanation:

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3 years ago
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Please help!
ladessa [460]
Area = length x width
the "big" rectangle: length = 15,  width = 14
the blue rectangle is: length = 15 - 4,  width = 14 - 6

Area of blue rectangle = (15 - 4)(14 - 6)
Answer: D
8 0
4 years ago
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Challenge A gold mine has two elevators, one for equipment and another for the miners. The
OLEGan [10]

Step-by-step explanation:

The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface

ii. The miners elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e speed = \frac{distance}{time}

time

distance

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 4 x 44

= 176

distance = - 176 feet

The distance of the miners elevator after 14 seconds is:

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miners elevator is deeper than that of the equipment.

6 0
3 years ago
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