Sequence = 40, 45, 48, 51, 59, 62, 69, 74
Median = 51+59 / 2 = 55
First quartile = 40, 45, 48, 51
So, it would be: 45 + 48 / 2 = 46.5
In short, Your Answer would be Option C
Hope this helps!
Answer: 12 friends.
Step-by-step explanation:
the data we have is:
Mei Su had 80 coins.
She gave the coins to her friends, in such a way that every friend got a different number of coins, then we have that:
The maximum number of friends that could have coins is when:
friend 1 got 1 coin
friend 2 got 2 coins
friend 3 got 3 coins
friend N got N coins
in such a way that:
(1 + 2 + 3 + ... + N) ≥ 79
I use 79 because "she gave most of the coins", not all.
We want to find the maximum possible N.
Then let's calculate:
1 + 2 + 3 + 4 + 5 = 15
15 + 6 + 7 + 8 + 9 + 10 = 55
now we are close, lets add by one number:
55 + 11 = 66
66 + 12 = 78
now, we can not add more because we will have a number larger than 80.
Then we have N = 12
This means that the maximum number of friends is 12.
Answer:
im sorry but i dont understand
First, you need to write to expressions to model each situation:
Plan A: 10+0.15x
Plan B: 30+0.1x
Next, set the expressions equal to each other and solve for x:
10+0.15x=30+0.1x
<em>*Subtract 0.1x from both sides to isolate the variable*</em>
10+0.05x=30
<em>*Subtract 10 from both sides*</em>
0.05x=20
<em>*Divide both sides by 0.05*</em>
x=400
The plans would have the same cost after 400 minutes of calls.
To find how much money the plans cost at 400 minutes, plug 400 into either expression. We'll use Plan A:
10+0.15(400)
10+60
70
The plans will cost $70.
Hope this helps!
The umber 10.5 can be written as
==> 21 / 2
==> 42 / 4
==> 63 / 6
==> 84 / 8
==> 105 / 10
and many, many other ways.
They ALL have the same value.
