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3 years ago

12

PLZZZZ HELP ASAP plzz

2 answers:

Anestetic [448]3 years ago

7 0

It’s D=45h!! All of them divided by the number on the left equal 45( will you please check my question on my page)

BARSIC [14]3 years ago

6 0

Answer:

no

Step-by-step explanation:

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Write any equation in slope intercept form that has a slope of3/2 and passes through (2,7)

Paha777 [63]

slope intercept form - (y = mx + b)

slope (m) is (3/2) So, y = 3/2x + b

To find b you plug in the x and y value (2,7)
7 = 3/2 × 2 + b

Isolate x on one side by finding the value of 3/2 × 2 which is 3.

Subtract 3 from both sides which leaves you with 4 = b, so the value of b is 4

Now the slope intercept form is (y = 3/2x + 4)

7 0

3 years ago

If a = 5 centimeters, w = 10 centimeters, and h = 6 centimeters, what is the area of the decorative paper he will require?

Marta_Voda [28]

Answer:

67

Step-by-step explanation:

3 0

4 years ago

Plz help it’s for my sister

Annette [7]

Answer:

11/24 - 6/24 = 5/24

Step-by-step explanation:

Common denominator is 24

24 * 1 = 24 11 * 1 = 24 11/24

4 * 6 = 24 1 * 6 = 24 6/24

New fractions are 11/24 and 6/24

Subtract them

11/24 - 6/24 = 5/24

6 0

3 years ago

Read 2 more answers

I will mark Brainliest to the correct answer and if they mark me brainliest five full stars please help

cricket20 [7]

it helps you because you can divide the bottom to the top or vice versa or you can divide x and y

4 0

3 years ago

Hi. I need help with these questions (see image)<br>Please show workings.<br>

pantera1 [17]

Answer:

see explanation

Step-by-step explanation:

Using the chain rule

Given

y = f(g(x)), then

$\frac{dy}{dx}$ = f'(g(x)) × g'(x) ← chain rule

and the standard derivatives

$\frac{d}{dx}$ ( $log_{a}$ x ) = $\frac{1}{xlna}$ , $\frac{d}{dx}$ (lnx) = $\frac{1}{x}$

(a)

Given

y = $log_{a}$ $\sqrt{(1+x)}$

$\frac{dy}{dx}$ = $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{d}{dx}$ ( $(1+x)^{\frac{1}{2} }$

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2}$ $(1+x)^{-\frac{1}{2} }$ × $\frac{d}{dx}$ (1 + x)

= $\frac{1}{lna\sqrt{(1+x)} }$ × $\frac{1}{2\sqrt{(1+x)} }$ × 1

= $\frac{1}{2lna(1+x)}$

= $\frac{1}{(1+x)lna^2}$

(b)

Given

y = ln sinx

$\frac{dy}{dx}$ = $\frac{1}{sinx}$ × $\frac{d}{dx}$ (sinx)

= $\frac{1}{sinx}$ × cosx

= $\frac{cosx}{sinx}$

= cotx

5 0

3 years ago