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2 years ago

How do I solve 6x—20=

2 answers:

6 0

Ok so you have 6x-20 it would be in the negatives so when you do that it stays negative because one negative stays as negative so you subtract -20 first then you multiply that by 6x which would give you negative 120 (-120

REY [17]2 years ago

4 0

Answer:

Can not be determined

Step-by-step explanation:

regularly, you would +20 to both sides, but without a full =, you cant solve. If the equation is 6x-20=0, x would equal 3 2/6.

Hope this helps!

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Which of the following equations could be solved for a radius? Select all that apply.

zalisa [80]

Answer:

A = π · (r²)

Step-by-step explanation:

$A =$ π · r² is the area of a circle.

While π · r² · h can also give you the radius, it can only do so for the Volume $V$ , not the Area $A$ .

$V=lwh$ doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.

$V=$ π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is $V=\frac{4}{3}$ · π · r³, not $V=$ π · r³.

$A=\frac{1}{2}*b*h$ only applies for triangles.

3 0

2 years ago

Read 2 more answers

15PTS PLEASE HELP ASAP! (dont write random answers pls) look at the pic attached:

LenKa [72]

Answer:

b) 1000m

Step-by-step explanation:

the law of sines.

you know all the angles and the length of the side a

7 0

2 years ago

Car A's fuel efficiency is 34 miles per gallon of gasoline, and car B's fuel efficiency is 23 miles per gallon of gasoline. At t

Verdich [7]

Answer:

22 more gallons.

Step-by-step explanation:

Given:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Question asked:

At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?

Solution:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

By unitary method:

Car A can travel 34 miles in = 1 gallon

Car A can travel 1 mile in = $\frac{1}{34} \ gallon$

Car A can travel 1564 miles in = $\frac{1}{34} \times1564=46\ gallons$

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Car B can travel 23 miles in = 1 gallon

Car B can travel 1 mile in = $\frac{1}{23} \ gallon$

Car B can travel 1564 mile in = $\frac{1}{23} \times1564=68\ gallons$

We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.

Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.

6 0

2 years ago

Please help , thank you so much !!

Shkiper50 [21]

Answer:

that is scientifically impossible

Step-by-step explanation:

one you can't add, subtract, round up, or use decimals write that down.

3 0

2 years ago

The answer to B and C

ArbitrLikvidat [17]

Assuming that the triangles are congruent, you can just look at the parts on each triangle to find the parts on the other triangle. The answers are yes, yes, and no. The triangles are obviously not drawn to scale, so just remember to never rely on it being so.

3 0

2 years ago