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3 years ago

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A restaurant charges a mandatory 15% tip for parties containing more than 6 people. A party of 10 people was charged $52.50 as a

tip. What is the amount of the bill?

1 answer:

bogdanovich [222]3 years ago

6 0

44.62 I’m not sure if I’m right

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long as 27 stickers, She gives 3 stickers to each of her friedns. Whith how many friends did Lin share her stickers.

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Answer:

27 divided by 3 is =9

Step-by-step explanation:

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F(x) = 4x + 7, g(x) = 3x^2 Find (f + g)(x)

kondor19780726 [428]

For the functions f(x) = 4x + 7 and g(x) = -9x + 11, find f(g(0)). For the functions f(x) = 3x2 - 7 and g(x) = -3x2 + 4, find f(g(2)). (Do NOT put commas in large numbers.)

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3 years ago

On a car trip, Ben drove 65 miles more than half the number of miles Steve drove. Together they drove 500 miles. How many miles

tatyana61 [14]

Answer:

210 miles

Step-by-step explanation:

Let's represent it mathematically.

Ben drove 65 miles more than half the number of miles Steve drove, so we represent it by

B = 65 + ½S

It is also said that together, they drove 500 miles, we represent it with.

B + S = 500

Now, we solve simultaneously.

Let's eliminate the ½ in Ben's drive. So we multiply the equation by 2.

2B = 130 + S.

Rearranging, we have

S = 2B - 130.

We substitute this value of S, in the second equation. So we have.

B + (2B - 130) = 500, open the brackets

B + 2B - 130 = 500

3B - 130 = 500, collecting the like terms

3B = 500 + 130

3B = 630

B = 630/3

B = 210 miles.

Therefore, Ben drove 210 miles.

Kindly vote Brainliest.

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3 years ago

Can someone help me with these problems? I'm in k12 and this assignment was in classkick, so if anyone already completed this an

kherson [118]

<em> </em><u><em>SOLVING QUESTIONS FROM 1ST PAGE</em></u>

Given the point B(-5, 0)

y = -3x - 5

Putting x = -5, and y = 0 in y = -3x - 5

0 = -3(-5) - 5

0 = 15 - 5

0 = 10 ∵Putting B(-5, 0) in y = -3x - 5 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

Given the point C<em>(-2, 1)</em>

y = -3x - 5

Putting x = -2, and y = 1 in y = -3x - 5

1 = -3(-2) - 5

1 = 6 - 5

1 = 1 ∵Putting C(-2, 1) in y = -3x - 5 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes ∵ L.H.S = R.H.S

Given the point D<em>(-1, -2)</em>

y = -3x - 5

Putting x = -1, and y = -2 in y = -3x - 5

-2 = -3(-1) - 5

-2 = 3 - 5

-2 = -2 ∵Putting D(-1, -2) in y = -3x - 5 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes ∵ L.H.S = R.H.S

<em> </em><u><em>SOLVING QUESTIONS FROM 2ND PAGE</em></u>

Given the point B(6, 18)

y = -2x + 18

Putting x = 6, and y = 18 in y = -2x + 18

18 = -2(6) + 18

18 = -12 + 18

18 = 6 ∵Putting B(6, 18) in y = -2x + 18 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

Given the point C(9, 24)

y = 2x + 6

Putting x = 9, and y = 24 in y = 2x + 6

24 = 2(9) + 6

24 = 18 + 6

24 = 24 ∵Putting C(9, 24) in y = 2x + 6 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes ∵ L.H.S = R.H.S

<em> </em><u><em>SOLVING QUESTIONS FROM 3RD PAGE</em></u>

Given the point D(2, 7)

y = 3x + 4

Putting x = 2, and y = 7 in y = 3x + 4

7 = 3(2) + 4

7 = 6 + 4

7 = 10 ∵Putting D(2, 7) in y = 3x + 4 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

<em> </em><u><em>SOLVING QUESTIONS FROM 4th PAGE</em></u>

<em>b. Which function could have produced the values in the table.</em>

<em>A. y = 3x + 4 </em>

<em>B. y = -2x + 18</em>

<em>C. y = 2x + 6</em>

<em>D. y = x + 9</em>

<em>The Table:</em>

<em>x y</em>

3 12

6 18

9 24

<em>Checking A) y = 3x + 4</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = 3x + 4</em>

For (3, 12)

y = 3x + 4

12 = 3(3) + 4

<em>12 = 13 </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

For (6, 18)

18 = 3(6) + 4

18 = 18 + 4

<em>18 = 22 </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

For (9, 24)

24 = 3(9) + 4

24 = 27 + 4

<em>24 = 31 </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no ∵ L.H.S ≠ R.H.S

So, the equation y = 3x + 4 could have not produced the all values in the table as the the ordered pairs in table do not satisfy(equate) the equation.

<em>Checking B) y = -2x + 18</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = -2x + 18</em>

<em>For (3, 12) </em>⇒ y = -2x + 18 ⇒ 12 = -2(3) + 18 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
<em>For (6, 18)</em> ⇒ y = -2x + 18 ⇒ 18 = -2(6) + 18 ⇒ 18 = 6 ⇒ <em>L.H.S ≠ R.HS</em>
<em>For (9, 24)</em> ⇒ y = -2x + 18 ⇒ 24 = -2(9) + 18 ⇒ 18 = 0 ⇒ <em>L.H.S ≠ R.HS</em>

So, y = -2x + 18 could have not produced all the values in the table, as (6, 18) does not equate the equation.

<em>Checking C) y = 2x + 6</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = 2x + 6</em>

<em>For (3, 12) </em>⇒ y = 2x + 6 ⇒ 12 = 2(3) + 6 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
<em>For (6, 18) </em>⇒ y = 2x + 6 ⇒ 18 = 2(6) + 6 ⇒ 18 = 18 ⇒<em> L.H.S = R.HS</em>
<em>For (9, 24) </em>⇒ y = 2x + 6 ⇒ 24 = 2(9) + 6 ⇒ 24 = 24 ⇒<em> L.H.S = R.HS</em>

So, y = 2x + 6 could have produced the values of in the table as all the orders pairs in the table satisfy/equate the equation.

<em>Checking D) y = x + 9</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = x + 9</em>

<em>For (3, 12) </em>⇒ y = x + 9 ⇒ 12 = 3 + 9 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
<em>For (6, 18) </em>⇒ y = x + 9 ⇒ 18 = 6 + 9 ⇒ 18 = 15 ⇒ <em>L.H.S ≠ R.HS</em>
<em>For (9, 24) </em>⇒ y = x + 9 ⇒ 24 = 9 + 9 ⇒ 24 = 18 ⇒<em> L.H.S ≠ R.HS</em>

So, y = x + 9 could have also not produced all the values in the table, as (6, 18) and (9, 24) do not satisfy/equate the equation.

So, from all the verification we conclude that:

<u>HENCE, ONLY </u><u>y = 2x + 6</u><u> COULD HAVE PRODUCED THE VALUES IN THE TABLE AS ALL THE ORDERED PAIRS OF THE TABLE SATISFY/EQUATE THE EQUATION.</u>

<em> </em><u><em>SOLVING QUESTIONS FROM 5th PAGE</em></u>

<em>What is the domain and range of the relation?</em>

{(-3, 7), (6, 2), (5, 1), (-9, -6)}

Domain: Domain is the set of all the x-coordinates of the ordered pairs of the relation, meaning the all first elements of the ordered pairs in a relation include in the domain of the relation.
Range: Range is the set of all the y-coordinate of the ordered pairs of the relation, meaning the all second elements of the ordered pairs in a relation include in the range of the relation.

As the given relation is {(-3, 7), (6, 2), (5, 1), (-9, -6)}

The <em>domain</em> is: {-3, 6, 5, -9}

<em>Note: generally, we write the numbers in ascending order for both the domain and range.</em>

The domain could also be written in order as: {-9, -3, 5, 6}

The <em>range</em> is: {7, 2, 1, -6}

The range could also be written in order as: {-6, 1, 2, 7}

Keywords: equation, point, ordered pair, domain, range

Learn more about points and equation from brainly.com/question/12597810

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3 years ago