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3 years ago

15

What is the area of the trapezoid?

1 answer:

liberstina [14]3 years ago

7 0

Answer:

Second option.

Step-by-step explanation:

You can use the formula for calculate the area of a trapezoid. This is:

$A_{(trapezoid)}=\frac{h}{2}(B+b)$

Where "B" is the larger base, "b" is the minor base and "h" is the height.

You can identify in the figure that:

$B=8units\\b=4units\\h=4units$

Then you can substitute values into the formula, getting that the area of the trapezoid is:

$A_{(trapezoid)}=\frac{4units}{2}(8units+4units)$

$A_{(trapezoid)}=24units^2$

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Write in standard form the equation of the parabola that contains the points (0, 0), (−1, −5), and (2, −2).

guapka [62]

Can you post a picture of the graph please

8 0

3 years ago

Evaluate a1 (r)^n-1 for a1 = 2, r= 3, and n = 4.<br> A. 216<br> B. 18<br> C. 32<br> D. 54

DaniilM [7]

Answer:

$54$

Step-by-step explanation:

$a_1 {r}^{n - 1} \\ 2 \times {3}^{4 - 1} \\ 2 \times {3}^{3} \\ 2 \times 3 \times 3 \times 3 \\ 2 \times 9 \times 3 \\ 18 \times 3 \\ = 54$

Hope this helps you.

Let me know if you have any other questions :-):-)

4 0

3 years ago

SOMEONE HELP!!!!!! Don’t use what websites! And please like list answer 1,2,3, and 4

harkovskaia [24]

Answer:

1. 24 2. 20 3. 1.75(I think) 4. 11

Step-by-step explanation:

3 might be incorrect but The others seem more correct than ever :)

8 0

3 years ago

Solve pls brainliest

tamaranim1 [39]

= 29/6 ×4

=29/3 ×2

=58/3

=19(1/3)

5 0

2 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

3 years ago