93 in base 10 converted into base 4 would 1131
Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
Answer:
Sue would have taken 15 hours to sew all the costumes.
Step-by-step explanation:
In 10 hours, Sue sewed 5 costumes (1 every 2 hours).
Sue= 5 costumes
Sue sewed in 10 hours, twice as many costumes as Anne in 16 hours. Then 5 is twice costumes than Anne produced. Therefore, Anne sewed 2.5 costumes.
Anne: 2.5 costumes
In total they had to sew 5+2.5= 7.5 costumes. Then Sue would have taken 7.5*2= 15 hours to sew them all.
If they y values are the same then you can equate these 2 equations
y = 8x and y = 2x + 2
8x=2x+2
because where they inersect their x and y values are the same
Answer: 800.
Step-by-step explanation: Round them both to the nearest ten. That is 40x20.