Step-by-step explanation:
Height of the cylinder A(h1)=5cm
CSA of cylinder A(CSA1)=18cm^2
Height of the cylinder B (h2)=10cm
CSA of cylinder B (CSA)=?
Since cylinder A and B are similar,
h1=xh2
or,5cm=x*10cm
or,x=1/2
Similarly,
CSA1=xCSA2
or,18cm^2=1/2*CSA2
or,CSA2=36cm^2
We khow that,
Volume of cylinder B (V2)= CSA2 * h2
=36cm^2*10cm
=36cm^3
Follow me for more solution like this.....
THANK YOU
Answer: 275d>1650
Step-by-step explanation:
because the question ask you a distance at least 1650 which means 275 times the days has to be greater than 1650.
Have a nice day.
P.S if this helped plz consider making me brainliest
Answer:
Step-by-step explanation:
a. (-6/2)*(1/3)*(36/2)=-18; b. (125/100)*(-2/2)
So we see the ratio of the sides of two similar octagons is 2:5 so let's say the first octagon has a side of 2 and the other has a side of 5. 2*8 = 16 and 5*8 = 40. 16:40 = 4:10 = and is again 2:5. So the answer is 2:5.
Answer: p-8
Step-by-step explanation:first thins problem is impossible without knowing the lifespan of a puma. But if you knew it oh let’s say it was 20 you would subtract the puma by 8.
