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weeeeeb [17]
3 years ago
9

2(4a - 4b) + 4(3a + 2b)plz solve this!!! ​

Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

2(4a - 4b) + 4(3a + 2b) = 20a

Step-by-step explanation:

2(4a - 4b) + 4(3a + 2b)

8a - 8b + 12a + 8b

8a + 12b - 8b + 8b

20a+ 0 = 20a

Thus, 2(4a - 4b) + 4(3a + 2b) = 20a

<u>-TheUnknownScientist</u>

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kupik [55]

Answer:

£33,000

Step-by-step explanation:

The money he gives to his daughter is represented by the 3 in the ratio so you divide £9000 by 3 to get £3000

The money he invests is represented by 11 in the ratio so you multiply £3000 by 11 to get £33,000

Hope this helps! :)

7 0
3 years ago
Please help! Solve x/12+1/3=−5/3. What is x?
Mama L [17]

the answer would be: x= -24

6 0
3 years ago
Read 2 more answers
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
The graph shows y = cot(x). Which of the following are true of its inverse? Check all that apply.
Mama L [17]

Answer:

Zeroes: None

Domain: All real numbers

Maximum: None

Step-by-step explanation:

5 0
3 years ago
Simple question, 4th.. Please help :( Thank you for the help so far! :D
aliya0001 [1]
I'm pretty sure the answer to your question would be A
3 0
2 years ago
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