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Allushta [10]
3 years ago
13

13 + 11s = -15 + 8s − 20

Mathematics
1 answer:
koban [17]3 years ago
3 0

<em>Answer,</em>

<em><u>S = -16</u></em>

<em>Explanation,</em>

<em><u>Step 1: Simplify both sides of the equation.</u></em>

<em>13 + 11s = − 15 + 8s − 20</em>

<em>13 + 11s = − 15 + 8s + − 20</em>

<em>11s + 13 = (8s) + (</em><em><u>− 15</u></em><em> + </em><em><u>− 20</u></em><em>) </em><em>(Combine Like Terms)</em>

<em>11s + 13 = 8s + − 35</em>

<em>11s + 13 = 8s − 35</em>

<em><u>Step 2: Subtract 8s from both sides.</u></em>

<em>11s + 13 − 8s = 8s − 35 − 8s</em>

<em>3s + 13 = − 35</em>

<em>Step 3: Subtract 13 from both sides.</em>

<em>3s + 13 − 13 = − 35 − 13</em>

<em>3s = − 48</em>

<em><u>Step 4: Divide both sides by 3.</u></em>

<em>3s/3 = −48/3</em>

<em>s = -16</em>


<u><em>Hope this helps :-)</em></u>


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4 0
2 years ago
56 points for whoever answers correctly !
vladimir2022 [97]

We need to use what we know about rectangles to get:

1)

  • Total length = 2*W + 8ft
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2) area = 2*W^2 + 24ft*W + 64ft^2

<h3>Working with rectangles:</h3>

We know that rectangles are defined by two measures, width W and length L.

Here we do know that the length of the pool is twice the width, and the width is W, then the length of the pool is:

L = 2*W

And we also have a sidewalk of 4ft all around the pool, now we want to get:

1) The total length and the total width.

This will be equal to the length/width of the pool <u>plus twice the width of the sidewalk</u> (we add it twice because is in both ends) then we have:

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2) Now we want to get an expression for the total area of the pool.

Remember that for a rectangle the area is just the product between the width and the length, so to get the area of the pool with the sidewalk we just take:

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area = 2*W^2 + 24ft*W + 64ft^2

This is the equation that gives the total area as a function of W, the width of the pool.

If you want to learn more about rectangles, you can read:

brainly.com/question/17297081

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harkovskaia [24]

Answer:

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b) $55,000

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Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

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    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

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No

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