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ArbitrLikvidat [17]
3 years ago
13

A ball is thrown into the air with an upward velocity of 80 feet per second. The function h = -16t^2 + 80t models the height h,

in feet, of the ball at time t, in seconds. When will the ball reach the ground? after 3 seconds after 4 seconds after 5 seconds after 6 seconds
Mathematics
2 answers:
adoni [48]3 years ago
5 0

Answer:

5 seconds

Step-by-step explanation:

The given height h, in feet, of the ball at time t, in seconds is defined by the function

h=-16t^2+80t

The height of the ball is 0 if it reached on the ground.

Substitute h=0 in the given function.

0=-16t^2+80t

0=-16t(t-5)

Using 0 product property, we get

-16t=0\Rightarrow t=0

(t-5)\Rightarrow t=5

It means ball will reach the ground at t=0(initial condition) and t=5.

Therefore, the ball will reach the ground after 5 seconds.

irakobra [83]3 years ago
3 0

The ball hits the ground when the height  h(t) = 0 , so

-16t^2 + 80t = 0

-16t(t - 5) = 0

t- 5 = 0  or -16t^2 = 0 (  here t = 0 which corresponds to when ball is thrown)

t - 5 = 0 gives:-

t = 5 seconds  (answer)

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