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Sindrei [870]
3 years ago
14

Given the table, what is the linear equation?

Mathematics
2 answers:
VLD [36.1K]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

zlopas [31]3 years ago
3 0
X + 3y

I think this is true. I haven’t done this in a few years.
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Wesimann Co. Issued 13-year bonds a year ago at a coupon rate of 7.3 percent. The bonds make semiannual payments and have a par
Harman [31]

Answer:

Current Bond price = $1155.5116

Step-by-step explanation:

We are given;

Face value; F = $1,000

Coupon payment;C = (7.3% x 1,000)/2 = 36.5 (divided by 2 because of semi annual payments)

Yield to maturity(YTM); r = 5.6%/2 = 2.8% = 0.028 (divided by 2 because of semi annual payments)

Time period;n = 13 x 2 = 26 years (multiplied by 2 because of semi annual payments)

Formula for bond price is;

Bond price = [C × [((1 + r)ⁿ - 1)/(r(r + 1)ⁿ)] + [F/(1 + r)ⁿ]

Plugging in the relevant values, we have;

Bond price = [36.5 × [((1 + 0.028)^(26) - 1)/(0.028(0.028 + 1)^(26))] + [1000/(1 + 0.028)^(26)]

Bond price = (36.5 × 18.2954) + (487.7295)

Bond price = $1155.5116

8 0
3 years ago
Is this a true statement X^2=1 if and only if x=1 or x=-1
Stells [14]

Answer:

yes the statement is true

Step-by-step explanation:

if you plug in 1^2 you are just multiplying 1 by its self

4 0
3 years ago
How do you write the equation in point slope form given slope=8, passing through (4,-1)?
xxMikexx [17]

Point slope form, y-y1 = m(x-x1)

Here, y1 = -1, x1 = 4, m=8

so, it would be: (y+1) = 8(x-4)

8 0
3 years ago
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swat32
I don't think parallelograms have symmetry
6 0
3 years ago
Which sets of values belong to the domain and range of a relation?
Nimfa-mama [501]

Answer:

Domain: input values, independent variables

Range: output vales, dependent variables

Step-by-step explanation:

Think of it like a graph: the domain are the x-values and the range is the y-values. if you're doing a problem with time, the time will go on the x-axis and cannot be influenced by the y-values, but the y-vales are depending on what the x-values are (independent/dependent). for the input/output, usually when solving equations on a graph, you plug in the x-value and find the y-value. you're INPUTTING the x-value to receive the OUPUT.

4 0
3 years ago
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