Given:
The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).
To find:
The area of the rectangle.
Solution:
Distance formula:

Using the distance formula, we get




Similarly,





Now, the length of the rectangle is
and the width of the rectangle is
. So, the area of the rectangle is:




Therefore, the area of the rectangle is 20 square units.
Answer:
like this?
Step-by-step explanation:

Solution:
Given PRQ is a triangle.
ST is a line parallel to RQ.



<u>Triangle proportionality theorem,</u>
<em>If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.</em>


Do cross multiplication, we get

Divide by 2x on both sides, we get

Answer:
5/6 w
Step-by-step explanation:
reorder the terms ( use the commuative property)
5/6 w
so the answer is 5/6 w
Answer:
Step-by-step explanation:
Perimeter is
P = 2L + 2W. We are given the perimeter as 180 feet, so
180 = 2L + 2W. Solve this for either L or W. I chose W, no reason...
180 - 2L = 2W so
90 - L = W Hold that thought. We'll come back to it in a minute.
Area is
A = LW. We are given the area as 1800 square feet, so
1800 = LW. Sub in 90 - L for W:
1800 = L(90 - L). Distribute to get a quadratic:

Get everything on one side and solve for the length by factoring:

Factor this however you like to factor quadratics, to get the length of
L = 30 and L = 60. First off, the length is longer than the width in general, so if we want to solve for the width, plug in 60 as L in the equation in bold print:
90 - 60 = W and
30 = W
So L = 60 and W = 30