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2 years ago

Solve the following systems of equations using substitution: x = 6 y = 2x - 3

Mathematics

2 answers:

Stolb23 [73]2 years ago

6 0

Answer:

y=9

Step-by-step explanation:

2(6)-3=9

Anvisha [2.4K]2 years ago

5 0

The answer is y=9
Y=2x-3
Y=2(6)-3
Y=12-3
Y=9

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What is the ratio of 1.5 inch screws to 2.5 inch screws?

Ugo [173]

Step-by-step explanation:

1.5 : 2.5

= 1.5/2.5

15/25

3/5

the ratio is 3 : 5

4 0

3 years ago

∠C and ∠D are vertical angles with m∠C=−3x+58 and m∠D=x−2 .<br><br><br><br> What is m∠D ?

11111nata11111 [884]

Vertical angles are equal

-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15

m < D = x - 2....15 - 2 = 13 <====
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4 0

3 years ago

Read 2 more answers

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago

It's geometry, not really sure what to do

Grace [21]

Answer:

K'= (-1,-1)

J'= (-1,-5)

L'= (0,-3)

Step-by-step explanation:

What you do here is, input the (x,y) coordinates into the translation.

For example, the original point K is (-3,5). Insert this into the translation.

(-3,5) → (-3+2, 5-8) = (-1,-3)

Repeat this for the next coordinates of L and J.

J= (-3,3)

(-3,3) → (-3+2, 3-8) = (-1,-5)

L= (-2, 5)

(-2, 5) → (-2+2, 5-8) = (0,-3)

5 0

3 years ago

Use De Moivre’s Theorem to compute the following: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%288cos%284%20%5Cpi%20%2F5%

Kipish [7]

Hello here is a solution :

6 0

3 years ago