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lina2011 [118]
4 years ago
13

(don't understand but I think its easy)Which of the following relations is a function?

Mathematics
2 answers:
Gala2k [10]4 years ago
7 0

Answer:

  B. {(1, 7), (2, 8), (4, 5), (0, 0), (3, 5)}

Step-by-step explanation:

You are right, it is easy. Any relation with a repeated first value is not a function.

A has (-3, -1) and (-3, -3), so the value -3 is a repeated first value.

C has (2, 5) and (2, 3), so the value 2 is a repeated first value.

D has (5, 8), (5, 9), and (5, -3), so the value 5 is a repeated first value.

None of A, C, or D is a relation that is a function. The correct choice is B, which has first values 0, 1, 2, 3, 4 -- none of which is repeated.

_____

If you plot points with repeated first values, you find they lie on the same vertical line. If a vertical line passes through 2 or more points in the relation, that relation is <em>not a function</em>. We say, "it doesn't pass the vertical line test."

A relation must pass the vertical line test in order to be a function. This is true of graphs of any kind, not just graphs of discrete points.

Dmitriy789 [7]4 years ago
5 0

<u>Answer:</u>

The correct answer option is B. {(1, 7), (2, 8), (4, 5), (0, 0), (3, 5)}.

<u>Step-by-step explanation:</u>

We are to determine whether which of the given relations in the possible answer options is a function.

We know that the x values of a function cannot be repeated. It means that for each output, there must be exactly one input.

Therefore, we will look for the relation where no x value is repeated.

Function ---> {(1, 7), (2, 8), (4, 5), (0, 0), (3, 5)}

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If (2i/2+i)-(3i/3+i)=a+bi, then a=<br>A. 1/10<br>B. -10<br>C. 1/50<br>D. -1/10​
Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

We need to find the value of a.

The LCM of (2+i) and (3+i)  is (2+i)(3+i)

=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}

Now rationalize the denominator by multiplying by 5-5i/5-5i

=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}

We are given

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

Now after solving we have:

\frac{1}{10}-\frac{i}{10}=a+bi

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0
4 years ago
Determine the value of s, the arc length (measured in inches) cut off in a circle with a radius of 3.4 inches by an angle with a
AleksandrR [38]

Answer:

Arc length s = 15.3 inches

Step-by-step explanation:

We know that length of an arc that subtends an angle θ radians at the center is given by

s=r\times \Theta

where

r is the radius of the circle

θ  is the angle subtended in radians

Thus applying values we get s=3.4\times \ 4.5radians

thus s = 15.3 inches

4 0
3 years ago
Given:
Molodets [167]

Answer:

Third one

<1 = <4 and <2 = <3

Step-by-step explanation:

When two parallel lines form a Z shape, we call the angles at the vertices of Z to be alternate interior angles, which are equal

5 0
3 years ago
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mafiozo [28]

Answer:

A 9x--12 i hope this helps

4 0
3 years ago
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