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Degger [83]
3 years ago
15

What is the simplified version of -4(8r + 3)

Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0

Answer:

-8-3

Step-by-step explanation:

-4(8r+3)

-32r-12

divide both sides by 4

-8-3

just olya [345]3 years ago
4 0

Answer:

-8-3

Step-by-step explanation:

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Arianna correctly simplified an expression. When she substituted mc020-1. Jpg into the simplified expression, the value was â€"4
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Answer:

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I need the answer and the explanation/ angle name pls help this is a quiz grade
Sever21 [200]

Step-by-step explanation:

The answer is :-

x and w : Dr. Alpha was meeting up with this patient in the library.

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Because x and w are Vertically Opposite Angles! And they are always same!

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3 years ago
Zeke had 9 dvds. His mother bought d more DVD. Write an expression that shows how many dvds zeke has now
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Answer: 9+d=x or x=9+d

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6 0
3 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
=-2\pi

So, the flux over the paraboloid alone is

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
4 years ago
Susie has 4 gallons of juice.How many cups of juice does she have?<br> ANSWER QUICKLY
IgorLugansk [536]

Answer: 64 cups

Step-by-step explanation:

Each gallon has 16 cups so you multiply 16 by 4 because there are 4 gallons and you get 64. Hope that helped. :)

5 0
3 years ago
Read 2 more answers
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