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2 years ago

PLEASE HELP ASAP ITS FOR A FINAL

Mathematics

1 answer:

azamat2 years ago

3 0

Answer:

1 The minimum number of fire extinguishers for Class A hazards for each floor of a building shall be determined by dividing the total floor area by the maximum area to be protected per extinguisher as determined by Table.

Step-by-step explanation:

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Lines l and m intersect at point p and are perpendicular. if a point q is reflected across l and then across m, what transformat

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Rotating 180 degrees about the point p.

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Evaluate the following: 3 Squared ÷ (2 + 1). 2 3 4 5

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3 years ago

Read 2 more answers

Solve by substitution. Please show work<br> -x+9y=-5<br> x-5y=1

kkurt [141]

Let's solve for x.

−x+9y=−5

Step 1: Add -9y to both sides.

−x+9y+−9y=−5+−9y

−x=−9y−5

Step 2: Divide both sides by -1.

−x ÷ −1 = −9y−5 ÷ −1

x=9y+5

THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)

Let's solve for x.

x−5y=1

Step 1: Add 5y to both sides.

x−5y+5y=1+5y

x=5y+1

Answer:

x=5y+1

I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)

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2 years ago

P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball

Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .