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3 years ago

Number 3 please!!! Best answer I will mark as brainliest

Mathematics

1 answer:

wolverine [178]3 years ago

3 0

A real world problem is considered a problem that can either be A: Solved in any method. B:has words and numbers So you would write for instant Charlie went to the store he bought 7 items that costed 21.99 how much money does he have left after spending it on the items? Can you solve it no you cannot why? Because it doesnt have the amount of money he was allowed to spend thats what missing information is. Now extra information is when there is something in the problem you DO NOT NEED to solve. Hope that helps you out.

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Answer please !!! i need help asap

maksim [4K]

Answer:

A. Undefined will be your answer

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In the orchard there were 10 rows with 12 trees in each row. How many trees were in the orchard?

Elodia [21]

Multiply 10 x 12 = 120 trees

3 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

2 years ago

Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?

romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions $\frac{40}{8}=\frac{x}{10}$ and $\frac{x}{40}=\frac{10}{8}$ . We are asked to find why the solutions to our given proportions are equal.