Assuming the fish pond is round, what you're given is the circumference.
So you know that 2<span>πr = 27.
We want to solve for the diameter, or d = 2r. We should isolate that.
2r = 27/</span><span>π
2r = 8.59 yards, or ~9 yards.</span>

3 0

3 years ago

Jordan is putting a fence around a garden that is shaped like a half circle and rectangle

grin007 [14]

Answer:

92 ft

Step-by-step explanation:

Assume the garden has the shape shown below.

The length of fencing equals the distance around three sides of the rectangle plus that around the semicircle.

1. Around the rectangle

Distance = 28 ft + 14 ft + 28 ft = 70 ft

2. Around the semicircle

For a circle.

C = 2πr

For the semicircle,

½C =½(2πr) = πr

D = 14 ft, so

r = 7 ft

$\text{Distance} = \dfrac{22}{7} \times \text{7 ft} = \text{22 ft}$

3. Total distance

Distance = 70 ft + 22 ft = 92 ft

Jordan will need 92 ft of fencing.

8 0

3 years ago

If mc022-1.j pg and mc022-2.j pg, what is the value of (f – g)(144)? –84 –60 0 48

Mashutka [201]

Answer:

Step-by-step explanation:

f(x) = √(x) + 12

g(x) = 2√(x)

(f-g)(x) = √(x) + 12 - 2√(x)

(f-g)(x) = 12 - √(x)

if x = 144

(f-g)(144) = 12 - √(144) = 12 - 12 = 0

5 0

3 years ago

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