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igor_vitrenko [27]

3 years ago

8

Calculate the number of atoms, please help in struggling

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

I think there are 13 atoms present.

Step-by-step explanation:

Please mark brainliest

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What is the length of the hypotenuse,c ? 3m 5m

UkoKoshka [18]

Answer:

square root of 34

Step-by-step explanation:

ok so S is for Squared

Cs= As+Bs

5s+3s= Cs

25+9=34

Cs=34

C= square root of 34

to get C we need to square root Cs

square root of 34

so C is 5.83

5 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

WILL GIVE BRAINLIEST FASTTTTT

Stells [14]

Answer: (x−2)(x−2)

The middle number is -4 and the last number is 4.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -4

Multiply together to get 4

Can you think of the two numbers?

Try -2 and -2:

-2+-2 = -4

-2*-2 = 4

Fill in the blanks in

(x+_)(x+_)

with -2 and -2 to get...

(x-2)(x-2)

Answer:

(x−2)(x−2)

so the answer is D.

6 0

3 years ago

Is jk the same length as kl? make sure you have mathematical proof to support your answer

lutik1710 [3]

Yes jk and kl are the same length because if you count the amount of units they reach from the first point to the last they both are 3 squared units/units how ever you want to call it.

7 0

3 years ago

Brainliest + 60 points

Elenna [48]

It’s the last option

3 0

3 years ago