❄ Hi there,
keeping in mind that the sum of complementary angles is 90°,
set up an equation, letting
be x –
{and we know that
}



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__________
Keeping in mind that a right angle is 90°,
set up an equation, letting
be x:
{and we know that
}



❄
the answer is 81x thank youuuuu lol
I believe it is 5 but i may need someone to double check <span />
Answer:
g(x), and the maximum is 5
Step-by-step explanation:
for given function f(x), the maximum can be seen from the shown graph i.e. 2
But for the function g(x), maximum needs to be calculated.
Given function :
g (x) = 3 cos 1/4 (x + x/3) + 2
let x=0 (as cosine is a periodic function and has maximum value of 1 at 0 angle)
g(x)= 3 cos1/4(0 + 0) +2
= 3cos0 +2
= 3(1) +2
= 3 +2
= 5 !
Answer:
Part A:
C= cash Sue earns
H = hours Sue works
C is dependent upon H because C only changes when H is changed.
Part B:
(0,0)
(1,6)
Part C:
C=6H